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faust18 [17]
3 years ago
15

So my mind went blank here, however im paying 30 points for doing it step by step, thanks in advance! And it's also two question

s so I'll bud in a 10 extra point for doing the second step by step.
Mr.Lander wants to buy new lab goggles that cost $31.50. He has $4.50 and plans to save $2.25 each week. How many weeks will it take him to save the money?


A. 14 weeks C. 11 weeks

B. 12 weeks D. 10 weeks


(step by step!)




Also this one,

-2(p-1) = 15

A: 13/2 B: 8


C: All real numbers D: -13/2

( step by step!)




Thank you, ill do 65 points instead!
Mathematics
2 answers:
ioda3 years ago
5 0

1.

2.25x+4.50 = 31.50

2.25x = 27

x = 27 / 2.25 = 12

Answer is B 12 weeks


2.

-2(p-1) =15

-2p +2 = 15

-2p =13

p = 13 / -2 =  -13/2

Answer is D -13/2


expeople1 [14]3 years ago
3 0
The first part is 14 weeks add the 31 and the 4 then divide it by the 2
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Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

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                          y = \frac{3Ln(x) + C  }{x}

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                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

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                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

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- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

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                        y ( x ) = \frac{3Ln(x) + 3 }{x}

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- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

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