I dont know if you know this, but there are 3 different 3's. So how can we figure out the question if we don't know which one is underlined?
More information is needed to properly answer the question!
It would be 4!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
Your final answer is either
x≥-2 if your initial inequality was
6x+2≤2(5-x)
OR
x≤-2
if your initial inequality was
6x+2≥2(x-2)
Step-by-step explanation:
As shown you have an equality, not an inequality.
-6x+2=2(5-x) distribute through parenthesis
-6x+2=2(5)+2(-x)
-6x+2=10-2x add 2x to both sides
2x-6x+2=10-2x+2x
-4x+2=10 subtract 2 from both sides
-4x+2-2=10-2
-4x=8 divide both sides by -4
-4x/(-4) = 8/(-4)
x = -2
With the ≥ or ≤ sign you would solve the exact same way
except for the point where when dividing both sides by
-4 requires you to reverse the inequality.
Your final answer is either
x≥-2 if your initial inequality was
6x+2≤2(5-x)
OR
x≤-2
if your initial inequality was
6x+2≥2(x-2)
We'll first clear a few points.
1. A hyperbola with horizontal axis and centred on origin (i.e. foci are centred on the x-axis) has equation
x^2/a^2-y^2/b^2=1
(check: when y=0, x=+/- a, the vertices)
The corresponding hyperbola with vertical axis centred on origin has equation
y^2/a^2-x^2/b^2=1
(check: when x=0, y=+/- a, the vertices).
The co-vertex is the distance b in the above formula, such that
the distance of the foci from the origin, c satisfies c^2=a^2+b^2.
The rectangle with width a and height b has diagonals which are the asymptotes of the hyperbola.
We're given vertex = +/- 3, and covertex=+/- 5.
And since vertices are situated at (3,0), and (-3,0), they are along the x-axis.
So the equation must start with
x^2/3^2.
It will be good practice for you to sketch all four hyperbolas given in the choices to fully understand the basics of a hyperbola.
