Written as a simplified polynomial in standard form, what is the result when

What is an equation of the line that passes through the point

Mnenie [13.5K]

Answer: y=3/2x+7

Step-by-step explanation:

To find the equation of the line that passes through the given point, let's first convert the given equation to slope-intercept form.

3x-2y=2 [subtract both sides by 3x]

-2y=-3x+2 [divide both sides by -2]

y=3/2x-1

Now that we have the equation in slope-intercept form, we know that the slope must stay the same because parallel lines NEVER touch. All we have to do is plug in the given point to find the y-intercept.

-2=3/2(-6)+b [multiply]

-2=-9+b [add both sides by 9]

b=7

Now, we know that the parallel equation is y=3/2x+7.

4 0

3 years ago

Find the value of x. round your answer to the nearest tenth. tan 46 degree = x/12

GrogVix [38]

Okay so start with getting the x by itself
tan46 = x/12
multiply both sides by 12
12tan46 = x
put that into a calculator and you get:
x=12.4

3 0

3 years ago

Read 2 more answers

A bag of uninflated balloons contains 10 red, 12 blue, 15 yellow and 8 green balloons. A balloon is drawn at random, what is the

tia_tia [17]

We have been given that a bag of uninflated balloons contains 10 red, 12 blue, 15 yellow and 8 green balloons.

We need to find the probability of drawing a red balloon.

We know that probability is given by

$\\
\text{Probability =} \frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Since we know that there are 10 red balloons. Therefore, our number of favorable outcomes is 10.

In order to find the total number of outcomes, we will add balloons of all colors.

Therefore, total outcomes are = $10+12+15+8 = 45$

We can now substitute the values of favorable outcomes and total outcomes in order to find the required probability.

$\\
\text{Probability =} \frac{\text{10}}{\text{45}} = \frac{2}{9}$

3 0

3 years ago

Read 2 more answers

Consider xưy" – 14xy' + 56y = 0. Find all values of r such that y=x" satisfies the differential equation for x > 0. Enter as

beks73 [17]

I bet the ODE is supposed to read

$x^2y''-14xy'+56y=0$

Then if $y=x^r$ , we have $y'=rx^{r-1}$ and $y''=r(r-1)x^{r-2}$ , and substituting these into the ODE gives

$r(r-1)x^r-14rx^r+56x^r=0\implies r(r-1)-14r+56=r^2-15r+56=0$

Solving for <em>r</em>, we find

$r^2-15r+56=(r-8)(r-7)=0\implies \boxed{r=8\text{ or }r=7}$

so that $y_1=x^8$ and $y_2=x^7$ are two fundamental solutions to the ODE. Thus the general solution is

$\boxed{y(x)=C_1x^8+C_2x^7}$

Given that $y(1)=4$ and $y'(1)=3$ , we get

$\begin{cases}4=C_1+C_2\\3=8C_1+7C_2\end{cases}\implies C_1=-25\text{ and }C_2=29$

So the particular solution is

$\boxed{y(x)=29x^7-25x^8}$

4 0

4 years ago

Whoever answers first gets brainly

Semenov [28]

Answer:

7.7- 3.51 goes to 8-4=4

3.5 -1.2 goes to 4-1 =3

22.78 - 14.12 goes to 23 - 14=9

16.208 - 3.652 goes to 16- 4= 12

4 0

3 years ago