All categories

2 years ago

If 60 is increased by 10%, what is the new amount

Mathematics

2 answers:

mylen [45]2 years ago

4 0

10 percent of 60 is 6. So 60+6= 66

lilavasa [31]2 years ago

3 0

<span>60 is increased by 10% is 66

Hope this helps ;)</span>

You might be interested in

I need this answered asap i will mark brainliest.

Harlamova29_29 [7]

I typed right on the problem set.

4 0

2 years ago

The houck family's train traveled 552 miles in 6 hours. The Roberts family traveled at 744 miles in 8 hours which family is trav

rusak2 [61]

Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.

Step-by-step explanation: Speed of Houck family's train = 552m/6hrs

speed of Robert family's train = 744m/8hrs.

Therefore considering Houck speed,

552miles = 6hours

1mile = (6 x 60)/552

= 360/552

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

For Robert

744miles = 8hours

1mile = ( 8 x 60 )/744

= (480/744)minutes

= 0.645

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

Conclusion: Both families were travelling at the same speed/rate.

To get that minutes in hour, just divide by 60 to get concert to hours.

6 0

2 years ago

Find the volume of a pyramid with a square base, where the area of the base is 7.9 m^2

Fofino [41]

The pyramid formula:
$\frac{1}{3} \times base \times height$

The volume in this case would be:

1/3×7.9×4
=79/30×4
=10.5333...
≈10.5 m^3

6 0

2 years ago

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

$P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]$

As, $P(z>1.28)=0.10$ [By z-table]

Then,

$\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712$

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0

2 years ago

Reflect the point C17,-5) over the x-axis

mamaluj [8]

Answer:

ur smart u got this

Step-by-step explanation:

keep trying and ask ur teacher for help

7 0

2 years ago