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Nat2105 [25]
3 years ago
11

READ THIS PLEASE.) Jada walks up to a tank of water that can hold up to 10 gallons. When it is active, a drain empties water fro

m the tank at a constant rate. When Jada first sees the tank it contains 7 gallons of water. Three minutes later, the tank contains 5 gallons of water.
PART A.) At what rate is the amount of water in the tank changing? Use a signed number, and include the unit of measurement in your answer.

PART B.) How many more minutes will it take for the tank to drain completely? Explain or show your reasoning.

PART C.) How many minutes before Jada arrived was the water tank completely full? Explain or show your reasoning.

LITTLE REQUEST PLEASE.)
SHOW YOUR WORK
I TRUST YOU GUYS....
THIS IS A FREE 45 POINT OPPURTUNITY
PLEASE HELP....
Mathematics
1 answer:
Inga [223]3 years ago
4 0
10-7=3, 7-5=2 so the pattern is -3,-2
Part b the answer is 6 mins because if you use the pattern -3,-2 and add it up minus 3 mins equals 2, and another 3 mins past and it’s -2 and 3 plus 3 is 6


Part C: 3 mins before she came the tank was full because if you switch the subtraction to addition it would be 7+3=10
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Step-by-step explanation:

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Help I need it now!!<br> T14= 46, and t20= 100, find t3, t7, and tn
Vinil7 [7]

Answer:

t_3 = -53\\\\\\t_7 = -17\\t_n= -80 +9n

Step-by-step explanation:

Arithmetic sequence:

       \sf \boxed{t_n=a+(n-1)d}

Here a is the first term and d is the common difference.

      t_{14}= 6    ⇒  \sf a + 13 d = 46  ------------(I)

     \sf t_{20} = 100 ⇒   a + 19d = 100 ---------(II)

Subtract equation (I) from (II)

(I1)    a + 19d = 100

(II)    a + 13d   =  46

      <u>-    -            -</u>

               6d = 54

                d = 54 ÷ 6

                 \sf \boxed{d = 9}

Substitute d = 9 in equation(I) and find 'a',

    a + 13*9= 46

     a + 117  = 46

              a = 46 - 117

              a = -71

         

\sf t_3 = -71 + 2*9

   = -71 + 18

   = -53

          \sf t_7 = -71 + 6*9

              = -71 + 54

              = -17

\sf t_n= -71 + (n-1)*9

    = -71 + 9*n - 1 *9

    = -71 + 9n - 9

    = -71 - 9 + 9n

     = - 80 + 9n

   

   

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1 year ago
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Answer:

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Step-by-step explanation:

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2 years ago
Assume the random variable X is normally distributed with mean mu equals 50 and standard deviation sigma equals 7. Compute the p
drek231 [11]

Answer:

The probability that <em>X</em> is less than 42 is 0.1271.

Step-by-step explanation:

The random variable <em>X </em>follows a Normal distribution.

The mean and standard deviation are:

E (X) = <em>μ</em> = 50.

SD (X) = <em>σ</em> = 7.

A normal distribution is continuous probability distribution.

The Normal probability distribution with mean µ and standard deviation σ is given by,

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To compute the probability of a Normal random variable we first standardize the raw score.

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These standardized scores are known as <em>z</em>-scores and they follow normal distribution with mean 0 and standard deviation 1.

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Thus, the probability that <em>X</em> is less than 42 is 0.1271.

The normal curve is shown below.

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iris [78.8K]

The answer is B. It is shifted up by 6*1.5-2-2 with is 9-2-2=5.

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1 year ago
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