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-BARSIC- [3]
4 years ago
12

Help quick !!!!!!!!!!!!!!

Mathematics
2 answers:
ser-zykov [4K]4 years ago
7 0

(7×5)+(7×9)

7×(5+9)=98

(7×5)+(7×9)=35+63=98

vfiekz [6]4 years ago
5 0

Answer: the correct answer is ( 7 * 5 ) + (7 * 9 )

Step-by-step explanation:

7 * ( 5+9) = (7 *  __) + ( 7 * __) = ( 7 * 5 ) + (7 * 9 )

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De una lamina rectangular de 10 centímetros de ancho y 14 de largo se construye una caja abierta, cortando un cuadrado de x cent
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How can the reader interpret the author's characterization of Meg?<span>She is casual about her appearance.
She prefers comfort over style in dressing up.
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3 years ago
Whiskers the cat weighs 2 and 2 over 3 kg.piglio weighs 4 kg. How many times as heavy as piglio is whiskers
ruslelena [56]

Answer:

Whiskers is two-third times as heavy as piglio is.

Step-by-step explanation:

Given:

Weight of whiskers is, W=2\frac{2}{3}\ kg

Weight of piglio is, P=4\ kg

In order to compare their weights, we have to divide both the weights and then express one weight in terms of the other.

Therefore, dividing whiskers weight by piglio's weight, we get:

\frac{W}{P}=2\frac{2}{3}\div 4\\\frac{W}{P}=\frac{8}{3}\div \frac{4}{1}(\textrm{4 can be rewritten as 4/1 in fraction form})

Now, when we divide two fractions, we replace the division sign by multiplication and reverse the second fraction. This gives,

\frac{W}{P}=\frac{8}{3}\times \frac{1}{4}\\\frac{W}{P}=\frac{8\times 1}{3\times 4}\\\frac{W}{P}=\frac{2}{3}

Now, expressing 'W' in terms of 'P', we multiply both sides by 'P. This gives,

W=\frac{2}{3}P

Therefore, the weight of whiskers is two-third times as heavy as piglio is.

4 0
3 years ago
What is the solution for x in the equation?​
Sveta_85 [38]

Answer:

3

Step-by-step explanation:

combine like terms (so 1/2 and 3/2): 2 - x = x - 4

add x to both sides: 2 = 2x - 4

add 4 to both sides: 6 = 2x

divide both sides by 2: 3 = x

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3 years ago
Which expression is equivalent to the following complex fraction?
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i hope this will help :)

3 0
4 years ago
Read 2 more answers
Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms oc
Anit [1.1K]

Answer:

a)\hat \sigma^2 =s^2 =30^2 = 900

b) 567.277 \leq \sigma^2 \leq 1690.224

Rounded to the nearest number would be:

567 \leq \sigma^2 \leq 1690

c) 23.818 \leq \sigma \leq 41.112

And rounded :

23.8 \leq \sigma \leq 41.1

Step-by-step explanation:

Data given and notation

s=30 represent the sample standard deviation

\bar x=290 represent the sample mean

n=20 the sample size

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Part a

The best point of estimate for the population variance is the sample variance, so on this case:

\hat \sigma^2 =s^2 =30^2 = 900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,19)" "=CHISQ.INV(0.95,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma \leq \frac{(19)(30)^2}{10.117}

567.277 \leq \sigma^2 \leq 1690.224

Rounded to the nearest number would be:

567 \leq \sigma^2 \leq 1690

Part c

In order to find the confidence interval for the deviation we just need to take the square root for the interval of the variance, and we got:

23.818 \leq \sigma \leq 41.112

And rounded :

23.8 \leq \sigma \leq 41.1

7 0
3 years ago
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