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Vlada [557]
3 years ago
10

an exponential function f is defined by f(x)=c^x where c is a constant greater than 1 if f (7) = 4 x f (5) what is the value of

c
Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 1

From the above, it can be seen that the nature of polynomial functions is dependent on its degree. Higher the degree of any polynomial function, then higher is its growth. A function which grows faster than a polynomial function is y = f(x) = ax, where a>1. Thus, for any of the positive integers n the function f (x) is said to grow faster than that of fn(x).

Thus, the exponential function having base greater than 1, i.e., a > 1 is defined as y = f(x) = ax. The domain of exponential function will be the set of entire real numbers R and the range are said to be the set of all the positive real numbers.

It must be noted that exponential function is increasing and the point (0, 1) always lies on the graph of an exponential function. Also, it is very close to zero if the value of x is mostly negative.

Exponential function having base 10 is known as a common exponential function. Consider the following series:

Derivative of logarithmic and exponential function 5

The value of this series lies between 2 & 3. It is represented by e. Keeping e as base the function, we get y = ex, which is a very important function in mathematics known as a natural exponential function.

For a > 1, the logarithm of b to base a is x if ax = b. Thus, loga b = x if ax = b. This function is known as logarithmic function.

Derivative of logarithmic and exponential function 2

For base a = 10, this function is known as common logarithm and for the base a = e, it is known as natural logarithm denoted by ln x. Following are some of the important observations regarding logarithmic functions which have a base a>1.

   The domain of log function consists of positive real numbers only, as we cannot interpret the meaning of log functions for negative values.

   For the log function, though the domain is only the set of positive real numbers, the range is set of all real values, i.e. R

   When we plot the graph of log functions and move from left to right, the functions show increasing behaviour.

   The graph of log function never cuts x-axis or y-axis, though it seems to tend towards them.

Derivative of logarithmic and exponential function 3

   Logap = α, logbp = β and logba = µ, then aα = p, bβ = p and bµ = a

   Logbpq = Logbp + Logbq

   Logbpy = ylogbp

   Logb (p/q) = logbp – logbq

Exponential Function Derivative

Let us now focus on the derivative of exponential functions.

The derivative of ex with respect to x is ex, i.e. d(ex)/dx = ex

It is noted that the exponential function f(x) =ex  has a special property. It means that the derivative of the function is the function itself.

(i.e) f ‘(x) = ex = f(x)

Exponential Series

Exponential Functions

Exponential Function Properties

The exponential graph of a function represents the exponential function properties.

Let us consider the exponential function, y=2x

The graph of function y=2x is shown below. First, the property of the exponential function graph when the base is greater than 1.

Exponential Functions

Exponential Function Graph for y=2x

The graph passes through the point (0,1).

   The domain is all real numbers

   The range is y>0

   The graph is increasing

   The graph is asymptotic to the x-axis as x approaches negative infinity

   The graph increases without bound as x approaches positive infinity

   The graph is continuous

   The graph is smooth

Exponential Functions

Exponential Function Graph y=2-x

The graph of function y=2-x is shown above. The properties of the exponential function and its graph when the base is between 0 and 1 are given.

   The line passes through the point (0,1)

   The domain includes all real numbers

   The range is of y>0

   It forms a decreasing graph

   The line in the graph above is asymptotic to the x-axis as x approaches positive infinity

   The line increases without bound as x approaches negative infinity

   It is a continuous graph

   It forms a smooth graph

Exponential Function Rules

Some important exponential rules are given below:

If a>0, and  b>0, the following hold true for all the real numbers x and y:

       ax ay = ax+y

       ax/ay = ax-y

       (ax)y = axy

       axbx=(ab)x

       (a/b)x= ax/bx

       a0=1

       a-x= 1/ ax

Exponential Functions Examples

The examples of exponential functions are:

   f(x) = 2x

   f(x) = 1/ 2x = 2-x

   f(x) = 2x+3

   f(x) = 0.5x

Solved problem

Question:

Simplify the exponential equation 2x-2x+1

Solution:

Given exponential equation: 2x-2x+1

By using the property: ax ay = ax+y

Hence, 2x+1 can be written as 2x. 2

Thus the given equation is written as:

2x-2x+1 =2x-2x. 2

Now, factor out the term 2x

2x-2x+1 =2x-2x. 2 = 2x(1-2)

2x-2x+1 = 2x(-1)

2x-2x+1 = – 2x

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siniylev [52]
The answer is 0, 1/3 of 21 is 7, 7-1=6, 1/2 of 12= 6, and 6-6=0. Hope this helps!
4 0
2 years ago
Which pair of angles are corresponding angles?
Effectus [21]

Corresponding angles are angles that are the same, and occupy the same relative position.

1 and 2: Incorrect - These are supplementary angles

3 and 5: Incorrect - These are same-side interior angles

2 and 6: Correct - These are corresponding angles

4 and 7: Incorrect - These are alternate interior angles

Hope this helps!! :)

7 0
2 years ago
5x + 4m = 43my + 6 solve for m
pav-90 [236]

9514 1404 393

Answer:

  m = (5x -6)/(43y -4)

Step-by-step explanation:

Subtract 4m+6 to separate m-terms from other terms.

  5x +4m -(4m +6) = 43my +6 -(4m +6)

  5x -6 = 43my -4m

  5x -6 = m(43y -4) . . . . factor out m

 (5x -6)/(43y -4) = m . . . . divide by the coefficient of m

7 0
2 years ago
Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot
Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

\frac{dm}{dt} = -\frac{t}{\tau}

Where:

m - Current mass of the isotope, measured in kilograms.

t - Time, measured in days.

\tau - Time constant, measured in days.

The solution of the differential equation is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}

\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }

The half-life of a isotope (t_{1/2}) as a function of time constant is:

t_{1/2} = \tau \cdot \ln2

t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2

The half-life difference between isotope B and isotope A is:

\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|

If \frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9, t_{A} = 33\,days and t_{B} = 43\,days, the difference in the half-lives of the isotopes is:

\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|

\Delta t_{1/2} \approx 65.788\,days

The approximate difference in the half-lives of the isotopes is 66 days.

4 0
3 years ago
Read 2 more answers
A loan of $900 will be repaid in 36 installment payments of $30.22 each. What the finance charge for the loan?
zimovet [89]
First you need to multiply 36 *$30.22=$1087.92
This gives you the total amount paid

Then subtract 1087.92-900=187.92
This gives you the amount of money you paid in finance charges.
3 0
3 years ago
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