How can the tiles be sorted? (I need it quick please)

What is the missing term in the quadratic expression below? (2x-3)(x-4)=2x^2+____ -12

cupoosta [38]

Answer:

ok

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).

Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5$

well then therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}$

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}$

6 0

2 years ago

A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a single-strand electric

larisa86 [58]

Answer:

525 x 1,050

A = 551,250 m²

Step-by-step explanation:

Let 'L' be the length parallel to the river and 'S' be the length of each of the other two sides.

The length of the three sides is given by:

$2S+L=2,100\\ L=2100-2S$

The area of the rectangular plot is given by:

$A=S*L\\A=S(2100-2S)\\A=2100 S -2S^2$

The value of 'S' for which the area's derivate is zero, yields the maximum total area:

$\frac{dA(S)}{dS}=\frac{d(2100 S -2S^2)}{dS}\\0= 2100 - 4S\\S=525$

Solving for 'L':

$L=2100-(2*525)\\L=1,050$

The largest area enclosed is given by dimension of 525 m x 1,050 and is:

$A = 525*1,025\\A=551,250\ m^2$

5 0

3 years ago

How to find restrictions for x?? 3. F(x)=2 sqrt x-4

stealth61 [152]

Answer:

none
none
x ≥ 4

Step-by-step explanation:

The restrictions placed on the independent variable in a function are those necessary to ensure that the function is defined for all allowed values of that variable.

In the graphs of problems 1) and 2), we see that the functions are defined for all values of x, so there are no restrictions.

__

3. For the function ...

$f(x)=2\sqrt{x-4}$

the value under the radical cannot be negative. The square root function is not defined for negative values, so the restriction is ...

x -4 ≥ 0

x ≥ 4 . . . . . . . add 4 to both sides of the inequality

4 0

3 years ago

EMERGENCY OOF HELP WITH MATH PIZZZ 5 + x^2= 2x^2+ 13 Provide steps and thanks

galben [10]

Answer:

false statement

Step-by-step explanation:

5+x^2=2x^2+13

5+x^2-2x-13=0

-8+x^2-2x^2=0

-8-x^2=0

-x^2=8

x^2=-8

this statement is false for any value of x because the power function with an even exponent is always postive or 0

4 0

3 years ago