The first thing to do is to calculate how many ways you can choose 3 people from a set of eight. In order to do this, we need to use the attached formula.
(The letter 'n' stands for the entire set and 'r' stands for the number of objects we wish to choose.)
So we wish to choose 3 people ('r') form a set of 8 ('n')
combinations = n! / r! * (n - r)!
combinations = 8 ! / (3! * 5!)
combinations = 8 * 7 * 6 * 5! / (3!) * (5!)
combinations = 8 * 7 * 6 / 3 * 2
combinations = 56
Now of those 56 combinations, the 3 people can finish in 6 different ways.
For example, persons A, B and C could finish
ABC or ACB or BAC or BCA or CAB or CBA
So to get the TOTAL combinations we multiply 56 * 6 which equals
336 so the answer is (a)
Answer:
nah its not cause in radical form that bih is 5√5
Step-by-step explanation:
A, in one day there are 6 clients and for each day multiplied it equals C for example if you were to plug in 1 for d
6(1)=6 and so on which shows the total clients.
So first you need to find 1/12 of 375. To do this you need to divide 375 by 12. So, your answer will be 31.25 per week.
B=-3
because you divide 27 by -9 to get y by its self
