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Vesnalui [34]
4 years ago
12

Expand and simplify the polynomial: (2x^3)(5x^4)

Mathematics
2 answers:
Roman55 [17]4 years ago
4 0
(2x^3)(5x^4)
= (2*5)(x^3*x^4)
= 10x^7
LekaFEV [45]4 years ago
3 0
Remember, (ab)(cd)=(a)(b)(c)(d), so we can expand
also
(x^m)(x^n)=x^{m+n}

so

(2x^3)(5x^4)=(2)(x^3)(5)(x^4)=(2)(5)(x^3)(x^4)=(10)(x^{3+4})=10x^7
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a parking meter contains $8.25 in dimes and quarters. after emptying the meter, the worker counts 51 coins. how many quarters an
Marianna [84]
<h3>30 dimes and 21 quarters are present</h3>

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

1 dime = $ 0.10

1 quarter = $ 0.25

The worker counts 51 coins

Therefore,

d + q = 51

d = 51 - q ---------- eqn 1

<em><u>A parking meter contains $8.25 in dimes and quarters</u></em>

Therefore,

0.10d + 0.25q = 8.25 -------- eqn 2

<em><u>Substitute eqn 1 in eqn 2</u></em>

0.10(51 - q) + 0.25q = 8.25

5.1 - 0.10q + 0.25q = 8.25

0.15q = 3.15

Divide both sides by 0.15

<h3>q = 21</h3>

Substitute q = 21 in eqn 1

d = 51 - 21

<h3>d = 30</h3>

Thus 30 dimes and 21 quarters are present

8 0
3 years ago
A train leaves at 17.22 and arrives at its destination at 18.14.
sattari [20]

Answer:

64.6 km/h

Step-by-step explanation:

18:14 = 18h 14'

1h = 60'

18h = 17h + 60'

18h14' = 17h + 60' ´14' = 17h 74'

then:

17h 74'

-17h 22'

= 0h 52'

the train travelled 56km at 52 minutes

56km/52minutes

1 hour = 60 minutes

52 minutes = 52/60 = 0.86667 hours

then:

56km/52minutes = 56km/0.86667hours

= 64.615 km/hours

5 0
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DedPeter [7]
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7 0
3 years ago
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Sauron [17]

Step-by-step explanation:

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3 0
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