Answer:
(0,1) doesn't lie on the graph.
Step-by-step explanation:
We have been given the logarithmic equation 
We can check which point lie on the graph of the given function by substituting x coordinates in the equation and find the corresponding y coordinate.
For x = 0

The value of log 0, is undefined, Hence, we'll not get a real value for this x value.
Hence, (0,1) doesn't lie on the graph.
For x = 27

Hence, (27,3) lie on the graph.
For x = 1

Hence, (1,0) lie on the graph.
Therefore, (0,1) doesn't lie on the graph.