Answer:
Tne most basic reason that cells ate stained is to enchance visualization of the cell or certain cellular components under a microscope.Cells may be also be stained to highlight metabotic processesor to differentiate between live and dead cells in a sample
hope it helps,and have a lucky day....
Answer:
Lysosomal enzymes are produced in the ER and transported to the Golgi complex to be finally incorporated into acidified vesicles
Explanation:
Lysosomes organelles are generated by the fusion of vesicles from the Golgi complex with endosomes. This organelle contains more than 50 types of hydrolytic enzymes capable of breaking down different macromolecules. Lysosomal enzymes are produced in the endoplasmic reticulum (ER), and then they are exported to the Golgi complex, where mannose-6-phosphate (M6P) label is added to be finally packaged into acidified vesicles. Mutations in the genes that encode for lysosomal enzymes are known to produce Lysosomal Storage Diseases (LSD) including Tay-Sachs disease.
egg whites
While it may seem daunting, a basic meringue is nothing more than a mixture of beaten egg whites and sugar.
Fungi is single celled micro organism, which grows in plants or soil. Fungi can be mostly found on soil or dead plants or dead matter.
Three characteristics of Fungi are:
- Fungi reproduce through spores.
- Fungi are mostly Eukaryotic or single celled.
- Fungi can play major role in recycling.
As a matter of terminology, albino guinea pig actually refers to a white fur guinea pig, whose genotype is homozygous recessive (bb).
If it crossed with a black fur guinea pig and gave 5 black fur offsprings, there is a good chance that the black fur parent is homozygous dominant (BB).
The Punnett square would be as follows:
B B
b Bb Bb
b Bb Bb
So they are all heterozygous black fur offsprings.
However, it is not impossible that the black fur parent be heterozygous, namely
B b
b Bb bb
b Bb bb
Giving a 50% chance on each colour. Thus it is possible (with probability 1/32) that all five offsprings are heterozygous black fur if one of the parents was heterozygous.
In the second case, a homozygous recessive and a homozygous dominant parent will never give a white offspring. So it is sure that the black fur parent is heterozygous, with the following Punnett square:
B b
b Bb bb
b Bb bb
With a 50% probability for each of Bb (black fur) and bb (white fur).
the distribution 4,3 demonstrates this perfectly.
