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3 years ago

Earth exerts a gravitational force on the moon. why doesn’t the force of gravity pull the moon into the earth?

1 answer:

5 0

The moon is orbiting the Earth so the moon's acceleration is towards the Earth but its velocity is in tangent to the Earth. Therefore the moon is in a constant free fall around the Earth instead of getting pulled toward Earth it orbits around it.

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A meteor is approaching Earth. Which statement about its motion is true?

ankoles [38]

the answer is b trust me its b

8 0

3 years ago

The fact that the total amount of energy in a system remains constant is a(n) experiment. theory. hypothesis. Or law.

Murrr4er [49]

Answer:

Explanation:

The law of conservation of energy states that the total amount of energy in a system remains constant.

8 0

3 years ago

If this speed is based on what would be safe in wet weather, estimate the radius of curvature for a curve marked 70 km/h . The c

olganol [36]

as it is given that curved marked the speed as v = 70 km/h

so we will first convert the speed into m/s

$v = 70 km/h = 19.44 m/s$

now we know that here friction force will provide centripetal force

$F_c = F_f$

As we know that centripetal force is given as

$F_c = \frac{mv^2}{R}$

$\frac{mv^2}{R} = \mu_k mg$

$\frac{v^2}{R} = \mu_k g$

$v^2 = \mu_k R * g$

$19.44^2 = 0.5* R * 9.8$

$378 = 4.9 * R$

$R = 77.1 m$

3 0

4 years ago

Read 2 more answers

Each wheel of a 320 kg motorcycle is 52 cm in diameter and has rotational inertia 2.1 kg m2 . The cycle and its 75 kg rider are

Amiraneli [1.4K]

Answer:

The value is $h = 32.91 \ m$

Explanation:

From the question we are told that

The diameter of each wheel is $d = 52 \ cm = 0.52 \ m$

The mass of the motorcycle is $m = 320 \ kg$

The rotational kinetic inertia is $I = 2.1 \ kg \ m^2$

The mass of the rider is $m_r = 75 \ kg$

The velocity is $v = 85 \ km/hr = 23.61 \ m/s$

Generally the radius of the wheel is mathematically represented as

$r = \frac{d}{2}$

=> $r = \frac{0.52}{2}$

=> $r = 0.26 \ m$

Generally from the law of energy conservation

Potential energy attained by system(motorcycle and rider ) = Kinetic energy of the system + rotational kinetic energy of both wheels of the motorcycle

=> $Mgh = \frac{1}{2} Mv^2 + \frac{1}{2} Iw^2 + \frac{1}{2} Iw^2$