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Nady [450]
3 years ago
13

Sound waves, water waves, and light waves are all alike in that they all

Physics
1 answer:
Paha777 [63]3 years ago
7 0
Sound and water waves are longitudinal waves, they require a medium to travel through and occilate particles 90 degrees to the wave motion
Light is a transverse wave. It doesnt require a medium to travel through.
All three reflect, refract and diffract


Light is difficult to think of because it acts in ways which waves cannot explain in some cirumstances. It acts like a particle (called photons) in some conditions, but acts like a normal sound or water wave does in others. Try not to get too caught up in light being a wave or a particle because even physists dont know how to explain it yet.
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Sound waves can be modeled by the equation of the form y=20sin(3t+theta). Determine what type of interference results when sound
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Explain how you should walk
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A step by step to walk

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One- Make sure your shoes are tied so that you dont trip

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How much kinetic energy the truck still has
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47.5kJ

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Before climbing the cliff

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8 0
3 years ago
A point charge +2Q is at the origin and a point charge −Q is located along the x axis at x = d as in the figure below. Find a sy
Akimi4 [234]

Answer: A symbolic expression for the net force on a third point charge +Q located along the y axis  

F_N=k_e\frac{Q^2}{d^2}\times \sqrt{[4+\frac{1}{4}-\sqrt{2}]}

Explanation:

Let the force on +Q charge y-axis due to +2Q charge be F_1 and force on +Q charge y axis due to -Q charge on x-axis be F_2.

Distance between the +2Q charge and +Q charge = d units

Distance between the -Q charge and +Q charge = \sqrt{2}d units

k_e= Coulomb constant

F_1=k_e\frac{(+2Q)(+Q)}{d^2}=k_e\frac{+2Q^2}{d^2} N

F_2=k_e\frac{(-Q)(+Q)}{(\sqrt{2}d)^2}=k_e\frac{-Q^2}{2d^2} N

Net force on +Q charge on y-axis is:

F_x=F_2sin 45^o=k_e\frac{-Q^2}{2d^2}\times \frac{1}{\sqrt{2}} N

F_y=F_1-F_2cos45^o

F_y=(F_1-F_2cos45^o)=(k_e\frac{+2Q^2}{d^2})-(k_e\frac{-Q^2}{2d^2}\frac{1}{\sqrt{2}})

F_N=\sqrt{F_x^2+F_y^2}

|F_N|=|k_e\frac{Q^2}{d^2}\times \sqrt{[4+\frac{1}{4}-\sqrt{2}]}|

The net froce on the +Q charge on y-axis is

F_N=k_e\frac{Q^2}{d^2}\times \sqrt{[4+\frac{1}{4}-\sqrt{2}]}

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