Explanation:
It is given that,
Weight of the rock in air, W = 110 N
Since, W = mg
m = 11.22 kg
We need to find the apparent weight of the rock when it is submerged in water. Apparent weight is equal to the weight of liquid displaced i.e.
d is the density of water, 
V is the volume of rock, 
M = 3.37 kg
The apparent weight in water, W = m - M
W = 76.93 N
So, the apparent weight of the rock is 76.93 N. Hence, this is the required solution.
Answer:
500 J
Explanation:
In the case of a rectilinear movement, the work is calculated as the product of Force (N) * movement (m). In your case, unless the angle between the force vector and the displacement vector is different from 0, the work is:
25 N * 20 m = 500 J
Explanation:
The ratio of the areas is the square of the ratio of the radii.
A/A = 3.16² = 9.99
The ratio of the volumes is the cube of the ratio of the radii.
V/V = 3.16³ = 31.6
The shuttles acceleration in the creases as the fuel is burned because the acceleration of the obect as produced by net force is directly proportional to the magnitude of the net force.
