Answer:
Step-by-step explanation:
product of slopes of perpendicular lines=-1
(t-5)/(3+4)×(2-3)/(-4-1)=-1
(t-5)/7×(-1/-5)=-1
(t-5)/35=-1
t-5=-1×35=-35
t=-35+5
t=-30
2.
slopes of parallel lines are equal.
(-2+3)/(t-4)=(-1-4)/(4+2)
1/(t-4)=-5/6
t-4=-6/5
t=4-6/5=(20-6)/5=14/5
3.
x>0,y<0
so P lies in4th quadrant.
except cos and sec all are negative.
so only cos and sec are positive.
Answer: x = 0
<u>Step-by-step explanation:</u>
4(7 - 3x) = 7(4 - 2x)
28 - 12x = 28 - 14x <em>distributed</em>
28 + 2x = 28 <em>added 14x to both sides</em>
2x = 0 <em>subtracted 28 from both sides</em>
x = 0 <em>divided both sides by 2</em>
The second question is number 3 for the polygon translation.
Question 3 is 2 units right and four units down.
i mean ig but 129.... ehh
Answer:
θ = 83°
Step-by-step explanation:
For acute angles, the sine of an angle is the cosine of its complement, and vice versa.
__
sin(θ) = cos(90° -θ) . . . . relation between sine and cosine
sin(θ) = cos(7°) . . . . . . . . given
90° -θ = 7° . . . . . . . . . matching arguments of cos( )
θ = 83° . . . . . . . . . add θ -7° to both sides
