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EastWind [94]
3 years ago
7

Edwin and Anthony are building a rectangular deck in their backyard.The Longer side is 2 more than 1/3 the perimeter. The shorte

r side is 1/10 of the perimeter. Know that the longer side is 9 ft longer than the shorter side. What is the Perimeter of the deck?
Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

Answer: The perimeter is 30ft.

Step-by-step explanation:

Let's define:

L = length of the longer side.

S = length of the shorter side.

P = perimeter

we know that for a common rectangle:

P = 2*S + 2*L

We aso know that:

L = 2ft + (1/3)*P

S = (1/10)*P

L = S + 9ft.

So we have a system, let's find the perimeter only using this system (So i will ignore the equation for the perimeter of a rectangle)

First, we can replace the third equation in the first equation, now we have a system with only two equations:

S + 9ft = 2ft + (1/3)*P

S = P/10

Now we can replace the second equation in the first equation, and get:

P/10 + 9ft = 2ft + P/3

Now let's solve this for P.

9ft - 2 ft = P/3 - P/10

7ft = P( 1/3 - 1/10) = P*( 10/30 - 3/30) = P*(7/30)

(30/7)*7ft = P = 30ft.

The perimeter is 30ft.

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Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are inches long, inches wide, and 8 inche
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Answer:

- The number of small boxes that will fill the large box 1 = 64

- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

For large box 1,

Length = L = 24.25 inches

Width = W = 18 inches

Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

Length = L = 20.5 inches

Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

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