The solution to the system of equation are x=2, y=0, z=6
<h3>System of equations</h3>
System of equations are equations that contains unknown variables.
Given the equations
3x+y+2z=8
8y+6z=36
12y+2z=12
From equation 2 and 3
8y+6z=36 * 1
12y+2z=12 * 3
______________
8y+6z=36
36y+6z= 36
Subtract
8y - 36y = 36 - 36
-28y =0
y = 0
Substitute y = 0 into equation 2
8(0)+6z=36
6z = 36
z = 6
From equation 1
3x+y+2z =8
3x + 0 + 2(6) = 8
3x = 8 - 12
3x = 6
x = 2
Hence the solution to the system of equation are x=2, y=0, z=6
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Answer:
any integer in between 29,30,31,32,33,34 will work.
Answer:
-48
Step-by-step explanation:
12 x 2=24
12 x 6= 72
24 - 72 = -48
