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3 years ago

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Ahmad rented a truck for one day. There was a base fee of $17.99, and there was an additional charge of 88 cents for each mile d

riven. Ahmad had to pay
$144.71 when he returned the truck. For how many miles did he drive the truck?
mile.

1 answer:

Masteriza [31]3 years ago

6 0

Answer:

266 miles

Step-by-step explanation:

(244.09-17.99)/0.85=266

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Jim sells used drones for 70% of the original manufacturer's purchase price of a new drone. Jim also sells new drones for 15% mo

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The function for the amount saved if they purchase a used drone rather than a new drone from Jim's store is f(x) = 0.45x

He sells used drones at 70% of the price (x).

So, the selling price of a used drone is:

$\mathbf{Used = 70\% \times x}$

Express percentage as decimal

$\mathbf{Used = 0.7 \times x}$

$\mathbf{Used = 0.7x}$

Also, he sells new drones at 15% more of the price (x).

So, the selling price of a new drone is:

$\mathbf{New= (1 + 15\%) \times x}$

Express percentage as decimal

$\mathbf{New= (1 + 0.15) \times x}$

$\mathbf{New= 1.15 \times x}$

$\mathbf{New= 1.15x}$

The amount saved is the difference between the prices of the drones.

So, we have:

$\mathbf{Saved =New - Old}$

This gives

$\mathbf{Saved =1.15x- 0.7x}$

Subtract

$\mathbf{Saved =0.45x}$

Express as a function

$\mathbf{f(x) = 0.45x}$

Hence, the function for the amount saved is f(x) = 0.45x

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Answer:

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Step-by-step explanation:

I find it easiest to solve these using the variable to represent the number of the most-expensive item. Let x represent the number of 33-cent stamps. Then the total value (in cents) is ...

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Mr. Akika had 11 24-cent stamps and 19 33-cent stamps.

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<em>Additional comment</em>

You seem to have several of these to solve. They all have a similar solution.

If we let x represent the number of higher-value items, N, the total number of items, V the total value, and v1 and v2 the individual values (v2 > v1), the equation is ...

v2(x) +v1(N -x) = V

x(v2 -v1) = V -v1·N

x = (V -v1·N)/(v2 -v1) . . . . generic solution

Using this formula in the problem here, we find ...

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