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zaharov [31]
3 years ago
8

How many repeating digits are in 41/11

Mathematics
2 answers:
adoni [48]3 years ago
5 0
There are 3 repeating digits
Komok [63]3 years ago
4 0
They're are two, 3.727272
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I am so confused. Can anyone help me??
natita [175]

Answer:

bro!  im in 7th grade i would try to help but im very stupid sorry for the dissopiontment

Step-by-step explanation:

8 0
3 years ago
Solving Rational Equations. LCD Method. Show work.<br><br><img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5x%7D%20%2B%5Cfrac%
Svet_ta [14]

using the LCD method.... well, there are a couple of ways, but let's simply add them up.

well, the denominators are 5x and 2x... so the only LCD will just be 10x, since it's divisible by both, so let's use that one.

\bf \cfrac{2}{5x}+\cfrac{7}{2x}=1\implies \stackrel{\textit{LCD of 10x}}{\cfrac{(2)2~~+~~(5)7}{10x}}=1\implies \cfrac{4+35}{10x}=1\implies \cfrac{39}{10x}=1 \\\\\\ 39=10x\implies \cfrac{39}{10}=x\implies 3\frac{9}{10}=x

5 0
3 years ago
Read 2 more answers
9 is the difference between two numbers, and their sum is 31. Find the numbers.
algol [13]

Answer:

The first number is 20, the second one is 11

Step-by-step explanation:

Let the first number be x and the second number be y

Since it says "9 is the difference between two numbers", the first equation will be x-y=9

It also says that "their sum is 31". That means the second equation will be x+y=31

here are the two equations:

x-y=9

x+y=31

You can solve this any way you like, but I'll show elimination

add the two equations

x-y=9

x+y=31

2x=40

divide by 2

x=20

Substitute 20 as x in one of the equations

20+y=31

subtract 20 from both sides

y=11

That means the two numbers are 20 and 11

Hope this helps!

4 0
3 years ago
The length of a rectangle is 3 cm more than twice the width. The area of the rectangle is 65 square centimeters. Find the dimens
polet [3.4K]

Answer:

5 cm and 13 cm

Step-by-step explanation:

Let b be the width of the rectangle.

Length = 3+2b

The area of the rectangle is 65 cm²

We need to find the dimensions of the rectangle. The area of a rectangle is given by :

A = lb

65=(3+2b)b\\\\65=3b+2b^2\\\\3b+2b^2-65=0\\\\b=5\ cm,-6.5\ cm

Neglecting the negative value, the width of the rectangle is 5 cm.

Length = 3+2b

=3+2(5)

=3+10

=13 cm

Hence, the dimensions of the rectangle are 5 cm and 13 cm.

6 0
3 years ago
F(x) = (64/63)(1/2)x, x = 1,2,3,...6. determine the requested values: round your answers to three decimal places (e.g. 98.765).
AleksandrR [38]

Calculator can help you

6 0
3 years ago
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