Given the numbers on the computer 123 is shown very complicated. Well it’s not given all the numbers and mind thinking if u add formula 1 that shows that I have no idea what to tell you and ur stuck
I sent help but no one answered :(
Jk, I got you fam
12(t + 2) + 4 ≥ - 8
12t + 24 + 4 ≥ - 8
12t + 28 ≥ - 8
12t ≥ - 8 - 28
12t ≥ - 36
t ≥ - 36 ÷ 12
t ≥ - 3
Solution:
t ≥ -3
Answer: a) 1 / ⁴⁰C₅ b) 0.33
Step-by-step explanation:
a) The sample space consists of all numbers 1-40.
Since any of the number can be taken from the sample space so each of five 5 distinct numbers we take has equal probability of occurring. So probability of each 5 numbers set we take will be equal to 1 / ⁴⁰C₅
b)
If we pick exactly 3 even number then that means other 2 will be odd.
So, we have sample space of 40 numbers out of which 20 are even and 20 are odd.
Now we have to pick 3 even out of 20 and 2 odd out of 20.
Probability = ²⁰C₃ * ²⁰C₂ / ⁴⁰C₅
Probability= 0.33
