Question

A company has a budget of $280,000 for computing equipment. Tablets cost $500 each, laptops cost $2000 each, and servers cost $5000 each. The company needs 5 times as many tablets as laptops, and two times as many laptops as servers. Set this problem up as a system of three linear equations, and use trial and error to determine the approximate number of each type of machine should be purchased.

Answer 1

Answer:

The number of tablets  200

the number of laptops  40

and, the number of servers 20

Step-by-step explanation:

Let the number of tablets be 'x'

the number of laptops be 'y'

and, the number of servers be 'z'

According to the given question

Total budget = $280,000

Tablets cost = $500 each

laptops cost = $2000 each

servers cost = $5000 each

Thus,

500x + 2000y + 5000z = 280,000 ..............(1)

also,

x = 5y  ................(2)

and,

y = 2z  

or

z = $\frac{\textup{y}}{\textup{2}}$   ............(3)

substituting y from 2 and 3 in equation 1,  we get

(500 × 5y) + (2000 × y) + (5000 × $\frac{\textup{y}}{\textup{2}}$ ) = 280,000

or

2500y + 2000y + 2500y = 280,000

or

7000y = 280,000

or

y = 40

substituting y in equation 2, we get

x = 5 × 40 = 200

substituting y in equation 3 we get

z = $\frac{\textup{40}}{\textup{2}}$

or

z = 20

hence,

the number of tablets  200

the number of laptops  40

and, the number of servers 20