did this answer your question...no. OK well that is your loss
Answer:
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
come on ! you can literally see that in the chart.
how many parts of the gray 3/8 are covered by the gray 1/4 ?
2 parts = 2/8 are clearly covered by 1/4.
2/8 is what part of 3/8 ?
it is the same question as "2 is what part of 3" ?
is 2 a quarter (1/4) of 3 ? no, 1/4×3 = 3/4 and not 2.
is 2 one third (1/3) of 3 ? no, 1/3 of 3 = 1/3×3 = 1 and not 2.
is 2 two thirds (2/3) of 3 ? ah, 2/3 × 3 = 2. that is correct !
is 2 three quarters (3/4) of 3 ? no, 3/4×3 = 9/4 and not 2.
once you have the same denominator, you can easily compare the numerators and ignore the denominators for such problems.
Answer:
88.88% probability that it endures for less than a year and a half
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

The next career begins on Monday; what is the likelihood that it endures for less than a year and a half?
One year has 52.14 weeks. So a year and a half has 1.5*52.14 = 78.21 weeks.
So this probability is the pvalue of Z when X = 78.21.



has a pvalue of 0.8888
88.88% probability that it endures for less than a year and a half
Answer:
The expectation is 
Step-by-step explanation:
From the question we are told that
The first offer is 
The second offer is 
The third offer is 
The number of tickets is 
The price of each ticket is 
Generally expectation is mathematically represented as

given that they just offer one
Now
given that they just offer one
Now
given that they offer five
Hence the expectation is evaluated as


Now given that the price for a ticket is 
The actual expectation when price of ticket has been removed is

