You need to provide "the following", otherwise other users cannot answer your question.
However, the Java operator for "not equal to" is "!=".
// For example.
if (1 != 2) {
System.out.println("1 doesn't equal 2");
}
The if-statement in the code above will always run, since 1 is not equal to 2.
Answer:
A) Malicious Association,
Hope this helps.
Explanation:
Answer:
#include <iostream>
using namespace std;
void divide(int numerator, int denominator, int *quotient, int *remainder)
{
*quotient = (int)(numerator / denominator);
*remainder = numerator % denominator;
}
int main()
{
int num = 42, den = 5, quotient=0, remainder=0;
divide(num, den, "ient, &remainder);
return 0;
}
Explanation:
The exercise is for "Call by pointers". This technique is particularly useful when a variable needs to be changed by a function. In our case, the quotient and the remainder. The '&' is passing by address. Since the function is calling a pointer. We need to pass an address. This way, the function will alter the value at the address.
To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.
Thanks! :)
My mans this is to long to read ); I got u tho lemme pick
