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prohojiy [21]
3 years ago
11

Shandra recently bought a brand-new digital camera from a local camera shop but when she got it home, she noticed the lens was j

ammed. What would be an effective way for her to handle this situation?
Computers and Technology
1 answer:
Scorpion4ik [409]3 years ago
4 0
Return to the camera shop and bring the camera in. mention that the lens was jammed and she would like a refund. she should stay calm and handle the situation gently, as to not anger the shop keep. if she returns the camera and gets a refund then no harm no foul, no money or product was lost.
hope this helps :)
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PLEASE HELP I NEED TO CHECK MY ANSWER ASAPPP
Vadim26 [7]

Functions are code segments that are executed when called or invoked

The function definition is not given; so, the output of the program cannot be outrightly determined.

However, the following are the possible scenarios.

  • The program would return 35.55 if the 2 represents the digits after decimal.
  • The program would return 36 if the 2 represents the significant digits.

It is unlikely for the program to return (a) 35.555 and (d) 40

Read more about functions at:

brainly.com/question/14284563

5 0
2 years ago
-Write a function is_perfect, which accepts a single integer as input. If the input is not positive, the function should return
Genrish500 [490]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// function

string is_perfect(int n)

{

   // string variables

   string str;

   // if number is negative

   if (n < 0)

   {

        str="invalid input.";

   }

   // if number is positive

   else

   {

      int a=sqrt(n);

      // if number is perfect square

      if((a*a)==n)

      {

          str="True";

      }

      // if number is not perfect square

      else

      {

          str="False";

      }

   }

   // return the string

     return str;

}

// main function

int main()

{

   // variables

int n;

cout<<"enter the number:";

// read the value of n

cin>>n;

// call the function

string value=is_perfect(n);

// print the result

cout<<value<<endl;

return 0;

}

Explanation:

Read a number from user and assign it to variable "n".Then call the function is_perfect() with parameter n.First check whether number is negative or not. If number is negative then return a string "invalid input".If number is positive and perfect square then return a string "True" else return a string "False".

Output:

enter the number:-3

invalid input.

enter the number:5

False

enter the number:16

True

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Explanation:

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