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3 years ago

Which of the following is an arithmetic sequence? A. 3, 5, 8, 13, 21 B. 6, 13, 19, 32, 51 C. 1, 4, 5, 9, 14 D. 3, 6, 9, 12, 15

Mathematics

2 answers:

Viefleur [7K]3 years ago

8 0

D is an arithmetic sequence since it is increased by 3 each time whereas the other sequences are not added continuously

Katen [24]3 years ago

3 0

D. Is the correct answer each number went up by 3

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The object on the right is made from a square-based pyramid joined to a cuboid.

spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

$V_{Cuboid} = l \times w \times h$

$V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3$

Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

$D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}$

Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

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Answer:

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Step-by-step explanation:

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Write an equation that expresses the following relationship. p varies jointly with the square of d and the cube of u In your equ

Veronika [31]

Answer:

$p= kd^{2}u^{3}$

Step-by-step explanation:

Using k as the constant of proportionality.

The expression that expresses the relationship : p varies jointly with the square of d and the cube of u.

Varies jointly means that p will change as 'd' and 'u' will change together with respect to their powers.

We get the expression as:

$p= kd^{2}u^{3}$

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