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3 years ago

What is the measure of the angle formed by the minute hand and hour hand of a clock in each case?

Mathematics

1 answer:

g100num [7]3 years ago

6 0

The measure is 90 degrees

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23 points please help simplify the square root sqrt (32x^2) if x>=0

dexar [7]

Answer:

4√2x.

Step-by-step explanation:

√32 = √2*√16 = 4√2.

√x^2 = x.

3 0

2 years ago

I will give brainliest away if you solve this for me please.

Elis [28]

Turn both equations into slope-intercept form [ y = mx + b ].

x + 3y = 3

~Subtract x to both sides

3y = 3 - x

~Divide 3 to everything

y = 1 - x/3

~Reorder

y = -1/3x + 1

4x + 3y = -6

~Subtract 4x to both sides

3y = -6 - 4x

~Divide 3 to everything

y = -2 - 4x/3

~Reorder

y = -4/3x - 2

Graph of the equations will be shown below. Note that the solution of graphing two equations will be where both equations intersect. Both lines intersect at (-3, 2), hence making that the solution.

Best of Luck!

8 0

3 years ago

Read 2 more answers

Sphere and a cylinder have the same radius and height. The volume of the cylinder is 64 meters cubed.

Mrrafil [7]

Answer:

C. 128/3 meters cubed

Step-by-step explanation:

The volume of a cylinder is denoted by: $V=\pi r^2h$ , where r is the radius and h is the height. We know it's equal to 64, so we can set that equal to V:

$V=\pi r^2h$

$64=\pi r^2h$

We know that the sphere and cylinder have the same height and radius. However, the "height" of a sphere is actually the same as its diameter, which is twice its radius. Then, we can replace h in the above equation with 2r:

$64=\pi r^2h$

$64=\pi r^2*2r=2\pi r^3$

$\pi r^3=64/2=32$

Now, the volume of a sphere is denoted by: $V=\frac{4}{3} \pi r^3$ , where r is the radius. From above, we know that $\pi r^3=32$ , so we can plug this into the equation: