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3 years ago

What is the measure of the angle formed by the minute hand and hour hand of a clock in each case?

Mathematics

1 answer:

g100num [7]3 years ago

6 0

The measure is 90 degrees

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The price of a coat increased from $78 to $92. What is the price increase percentage?

svetlana [45]

Answer:

18%

Step-by-step explanation:

Percent change can be found using the following formula:

$\frac{original-new}{original}*100$

Original represents the initial cost where new represents the new cost. We multiply the answer by 100 to get the percentage:

$\frac{92-78}{78}*100$ = 18%

6 0

3 years ago

-11b+7=40 b=? help, please

serious [3.7K]

Answer: -3

Step-by-step explanation:

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3 years ago

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Negation of no planes have three wheels

anygoal [31]

Ohyeah free points bruhoo

5 0

3 years ago

Can someone please help me with this ❤️❤️

kherson [118]

Answer:

See below for answers

Step-by-step explanation:

y=5(2)ˣ

y=5(2)⁻²=5(1/2²)=5(1/4)=5/4

y=5(2)⁻¹=5(1/2¹)=5(1/2)=5/2

y=5(2)⁰=5(1)=5

y=5(2)¹=5(2)=10

y=5(2)²=5(4)=20

8 0

2 years ago

Integrate sin^-1(x) dx please explain how to do it aswell ...?

Lynna [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2264253

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}$

Trigonometric substitution:

$\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}$

then,

$\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}$

So the integral $\mathsf{(ii)}$ becomes

$\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}$

Integrate $\mathsf{(ii)}$ by parts:

$\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}$

$\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}$

Substitute back for the variable x, and you get

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=sin^{-1}(x)\cdot x+\sqrt{1-x^2}+C}\\\\\\\\ \therefore~~\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=x\cdot\,sin^{-1}(x)+\sqrt{1-x^2}+C\qquad\quad\checkmark}$

I hope this helps. =)

Tags: integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus

6 0

3 years ago