Which pair of equations represents perpendicular lines?

Mathematics

1 answer:

Kaylis [27]3 years ago

8 0

Your answer for this is the third one or C.

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5. In the figure, . Solve for . Show your work.

natima [27]

Answer:

Step-by-step explanation:

6/10=9/x

cross multiply

6x=9*10

6x=90

x=90/6x=15

3 0

3 years ago

someone is eating a 50 gram chocolate bar which contains 30% cocoa how many grams of cocoa is in the chocolate bar

DIA [1.3K]

Well , 10% is 5 g so if you times those 5 g by 3 it is 15 g there are 15 grams of cocoa in the chocolate bar

3 0

3 years ago

Read 2 more answers

Please help, I’ll mark your answer as brainliest!

statuscvo [17]

Answer:

$(x-230)^2+(y-220)^2=6100$

Step-by-step explanation:

The equation for a circle is $(x-h)^2+(y-k)^2=r^2$ , where $(h,k)$ is the vertex of the circle and $r$ is the radius. Immediately, since the center of the circle is given, we know what $h$ and $k$ are. $h$ is 230 and $k$ is 220.

The only thing we need to find is the radius, which will just be the distance from the center (230,220) to a point on the circumference (170,170). The distance between them can be calculated using the <u>distance formula</u>, which is really just the <u>Pythagorean Theorem</u> rearranged. The formula states that $d=\sqrt{x^2+y^2}$ , where $x$ is the change in the x-coordinates of the two points and $y$ is the change in the y-coordinates of the two points. Plug-in $x$ for 60 and $y$ for 50 to get $d=\sqrt{50^2+60^2}$ . Solve for $d$ , arriving at $\sqrt{6100}$ . Therefore, the radius of the circle is $\sqrt{6100}$ .