$\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad

\cfrac{1}{a^{ n}}\implies a^{-{ n}}\\
---------------\\
thus\\
(x+4)^{-1}\implies \cfrac{1}{x+4}
\\\\
$
$\bf if\qquad \cfrac{1}{0} \implies$ undefined

so.. what value of "x" makes x+4 to 0?

the domain will be, all real numbers, except that value

about the range, "y" will take, whateve "x" can provide.. in this case... I think is all real numbers, except 0, because, if you give a few big values to "x", the fraction will simply have a bigger and bigger denominator, making the fraction smaller and smaller, ever approaching 0, but never getting there

7 0

3 years ago

Which of the following functions has an amplitude of 5 and passes through the point (0,0)?

dlinn [17]

Im gonna need to know what the choices are

5 0

3 years ago