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Pani-rosa [81]
3 years ago
7

Estimate how many 12-inch rulers will be about the same length as a sheet of paper.

Mathematics
2 answers:
vfiekz [6]3 years ago
6 0
A standard sheet of paper is 11 by 8.5 inches.
The estimated length of a standard sheet of paper is one 12 inch ruler.

lbvjy [14]3 years ago
4 0
About one standard ruler is the ESTIMATED length of a piece of paper.

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Perform the following operation, and report the answer to the correct number of significant figures. 3.47 x 6.7
kobusy [5.1K]

Answer:

23

Step-by-step explanation:

3.47 = 3 sig. figs.

6.7 = 2 sig. figs.

Since these two numbers are being multiplied, you would round to the smallest number of sig. figs. of the two. In this case, it would be 2 significant figures.

3.47 * 6.7 = 23.249 (dont forget to round to 2 sig. figs. ) --> 23

6 0
3 years ago
What is the value of 2 in 0.812 writen as a fraction
Zanzabum
Thousandths place hope e I helped
5 0
3 years ago
Read 2 more answers
Can someone tell me what the answer is for x/-9≥3 as a simplified answer
Nostrana [21]
X/-9 ≥3 multiply both side by -9 to get rid of fraction
-9/1•x/-9 ≥-9•3
Cross cancel -9 on left side
x ≥ -27
6 0
3 years ago
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
Please help meeeeeee
LuckyWell [14K]

Answer:

it's the bottom left one

Step-by-step explanation:

Im just a kid, don't ask

So -1/4x+1/2 x would be 1/4 x because -0.25+0.5=0.25

translating 2/3 into 4/6, so we do 4/6-2/6 which would be 1/2.

:) Im an idiot lol

5 0
2 years ago
Read 2 more answers
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