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3 years ago

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A group of students wants to determine the favorite snack food at their school. They know they should use a sample because the s

tudent population at their high school is 5,000. What is the best way for them to get a random sample of 100 students?

1 answer:

s2008m [1.1K]3 years ago

3 0

Divide 5,000 to 100 and u will get your answer

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So I need help pls show ur work

Ad libitum [116K]

Answer:

x = – ⅓

Step-by-step explanation:

The solution to the expression can be obtained as follow:

–3.1x + 7 – 7.4x = 1.5x – 6(x – 3/2)

Clear bracket

–3.1x + 7 – 7.4x = 1.5x – 6x + 9

–3.1x – 7.4x + 7 = –4.5x + 9

–10.5x + 7 = –4.5x + 9

Collect like terms

–10.5x + 4.5x = 9 – 7

–6x = 2

Divide both side by –6

x = 2 / –6

x = – ⅓

Thus, the solution to the equation is –⅓

7 0

3 years ago

Can someone help me with this I’m really bad in geometry

Crank

I redrew the triangle (just turned it around it make it easier to understand).

7 0

3 years ago

Solve the equation 3 - 4-587<br> 3.87<br> b. 0.55, -0.55<br> a.<br> C. 1.53,-1.53<br> d. 4.98

dexar [7]

Answer: X = 0

Let me know if it’s correct

8 0

3 years ago

Y=x^2-3x-6<br><br>x+y=2<br><br><br>Help 50 Points!!! Show Work

Alborosie

X + y = 2 —> y = 2 - x
insert to first equation
2-x=x^2-3x-6
x^2 - 3x - 6 - 2 + x = 0
x^2 - 2x - 8 = 0
(x-4)(x+2) = 0
x = 4 or x = -2

5 0

3 years ago

Read 2 more answers

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

1 year ago