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Evaluate the indefinite integral:

Substitution:

So the integral

becomes


I hope this helps. =)
Tags: <em>indefinite integral fraction rational substitution power differential calculus</em>
Answer:
Step-by-step explanation: I think the answer is a
We have no clue because you have not said what the speed/pace is. At a speed of 17.23 mph you will bike 112miles in 6.5 hours.
Answer:
240 minutes/ 4 hours
Step-by-step explanation: