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lana66690 [7]
3 years ago
13

The area of a square poster is 59 in.squared 2. Find the length of one side of the poster to the nearest tenth of an inch.

Mathematics
2 answers:
mafiozo [28]3 years ago
6 0
The answer would be 7.4 , because if you divide 59 by 2 that's the perimeter so divide that by 4 and round it. That should be the answer.  
amm18123 years ago
6 0
Length of each side of square is 7.6 inch.

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3/4x = 1/5. X=__<br><br> A. 3 3/4<br><br> B. 11/20<br><br> C. 4/15<br><br> D. 3/20
gizmo_the_mogwai [7]

Answer:

C

Step-by-step explanation:

transposition

3x/4=1/5

xc=yc

15x/20×20=4/20×20

15x=4

x=4/15

4 0
2 years ago
-7x + 2y = 4<br> What is the answer
storchak [24]

Answer:

hi if you want to solve fore x and y there must be 2 equations .

Step-by-step explanation:

so that you could solve them simultaneously

-7x + 2y = 4

here 2y - 4 = 7x

( 2y -4)/7 = x

7 0
3 years ago
Read 2 more answers
Simplify, then substitute
trapecia [35]

Answer:

5x +17

Step-by-step explanation:

4 0
3 years ago
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3.9 times 10 to the seventh power
ra1l [238]

Hey there!

3.9 times 10 to the seventh power is equivalent to the equation 3.9 × 10^{7}

The seventh power indicates the amount of times the decimal moves to the right of 3.9, so that expression would be equivalent to 39,000,000.

Hope this helps!

3 0
3 years ago
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The sum of three consecutive odd integers is 81. what is the value of the largest integer?
RoseWind [281]

I don't know how your teacher chooses to solve this problem (or your text) but I do it this way.

Divide 81 by 3. You get 27.

Use 27 as your middle integer and go one odd integer up and down for the other 2.

25, 27, 29

the largest would be 29.

This works because 3 of the middle number equals 81, so the middle number plus a number 2 greater and a number 2 less would still be the same as adding 3 of the same number.

Check by adding the 3 numbers.

25 + 27 + 29 = 81

4 0
4 years ago
Read 2 more answers
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