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lana66690 [7]
3 years ago
13

The area of a square poster is 59 in.squared 2. Find the length of one side of the poster to the nearest tenth of an inch.

Mathematics
2 answers:
mafiozo [28]3 years ago
6 0
The answer would be 7.4 , because if you divide 59 by 2 that's the perimeter so divide that by 4 and round it. That should be the answer.  
amm18123 years ago
6 0
Length of each side of square is 7.6 inch.

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What is the area of a rectangle with length 112 foot and width 34 foot?
Nastasia [14]

Answer:

<u>3808ft²</u>

Step-by-step explanation:

Formula: A=L×W

<u>A=</u> area

<u>L=</u>  length

<u>W=</u> width

A= 112 × 34= <u>3808ft²</u>

8 0
3 years ago
Here is a sketch of y=x^2+bx+c The curve intersects
atroni [7]

Answer:

y = 18  and  x = -2

Step-by-step explanation:

y = x^2+bx+c   To find the turning point, or vertex, of this parabola, we need to work out the values of the coefficients b and c. We are given two different solutions of the equation. First, (2, 0).  Second, (0, -14). So we have a value (-14) for c. We can substitute that into our first equation to find b. We can now plug in our values for b and c into the equation to get its standard form. To find the vertex, we can convert this equation to vertex form by completing the square. Thus, the vertex is (4.5, –6.25). We can confirm the solution graphically     Plugging in  (2,0) :

y=x2+bx+c  

0=(2)^2+b(2)+c  

y=4+2b+c  

-2b=4+c  

b=-2+2c  

Plugging in  (0,−14) :

y=x2+bx+c  

−14=(0)2+b(0)+c  

−16=0+b+c  

b=16−c  

Now that we have two equations isolated for  b , we can simply use substitution and solve for  c .   y=x2+bx+c  16 + 2 = y   y = 18  and  x = -2

4 0
2 years ago
Shelby will take a total of 6 tests. On the first 5 tests, her scores were: 80, 85, 73, 78, 90. If she wants a mean grade of 80,
Andrew [12]

Answer:

74

Step-by-step explanation:

4 0
3 years ago
Find a range of th fucunction f(x)=4x-1 for the domain{-1,0,1,2,3}
vlada-n [284]
F(x) = 4x - 1

All you have to do is substitute the values in the domain for x in the function.

f(-1) = 4(-1) - 1
f(-1) = -4 - 1
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f(0) = 4(0) - 1
f(0) = -1

f(1) = 4(1) - 1
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And so on.
7 0
3 years ago
WHATS THE PERIMITER PLS HELP ME
mihalych1998 [28]
I believe the answer is c
4 0
3 years ago
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