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Vinil7 [7]
3 years ago
12

Solve for the x-values of the x-intercepts of the parabola whose equation is y=x^2+5x+6.

Mathematics
1 answer:
k0ka [10]3 years ago
3 0

Answer:

x\ values\ of\ x-intercepts\ are\ x=-2\ and\ x=-3

Step-by-step explanation:

x-intercepts: The point at which curve passes through the x-axis that is when y=0.

The given curve is y=x^2+5x+6.

To get x-intercepts substitute y=0.

x^2+5x+6=0\\\\x^2+3x+2x+6=0\\\\x(x+3)+2(x+3)=0\\\\(x+3)(x+2)=0\\\\Hence\ x=-3,\ x=-2

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