Question

Solve for the x-values of the x-intercepts of the parabola whose equation is y=x^2+5x+6.

Answer 1

Answer:

$x\ values\ of\ x-intercepts\ are\ x=-2\ and\ x=-3$

Step-by-step explanation:

x-intercepts: The point at which curve passes through the $x-axis$ that is when $y=0$.

The given curve is $y=x^2+5x+6$.

To get x-intercepts substitute $y=0$.

$x^2+5x+6=0\\\\x^2+3x+2x+6=0\\\\x(x+3)+2(x+3)=0\\\\(x+3)(x+2)=0\\\\Hence\ x=-3,\ x=-2$