A jar contains 45 red candies and 60 black candies. Suppose a candy is selected at random. What are the odds against selecting a
red candy?
1 answer:
Answer:
3:4.
Step-by-step explanation:
To work this out we need to find the highest multiple of 45 and 60.
15 is the largest number that goes into both of them so what we are going to do now is divide both number by 15.
45 divided by 15 = 3
60 divided by 15 = 4
Therefore the odds of selecting a red candy is 3:4.
Hope that helps. x
You might be interested in
Answer:
Nothing more can be done
A. x = -1; x = 3
B. x = 5; x = -4
C. x = -1; x = 4
D. x = -6; x = 4
: Hope this helps :)
Answer:
Is b
Step-by-step explanation:
Answer:
yes it is a right triangle if you look closely at triangle ABC there is a right triangle mark the little square
R+L=12
R=12-L
48(12-L)+36L=528
576-48L+36L=528
-48L+36L=528-576
-12L=-48
L=4
R+4=12
R=12-4
R=8