Question

A tritium nucleus is formed by combining two neutrons and a proton. the mass of this nucleus is 9.106 × 10–3 universal mass unit less than the combined mass of the particles from which it is formed. approximately how much energy is released when this nucleus is formed.

Answer 1

E = m c²

where E = energy released

m = mass of the nucleus

C= velocity of light

m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg

C = 3 x 10⁸ m/s and C² = 9 x 10¹⁶

E = 1.37 x 10 ⁻¹² J

Answer 2

Answer : The amount of energy released is, $136.043\times 10^{-14}J$

Explanation :

According to the Einstein equation, the energy is equal to the product of mass and the square of the speed of light.

The mathematical expression is :

$E=m\times c^2$

where,

E = energy

c = speed of light = $3\times 10^8m/s$

m = mass of nucleus = $9.106\times 10^{-3}amu$

Conversion the mass of nucleus from 'amu' into 'Kg' :

As, $1amu=1.66\times 10^{-27}Kg$

So, $9.106\times 10^{-3}amu=(9.106\times 10^{-3})\times (1.66\times 10^{-27})Kg$

Now put all the given values in the above formula, we get the amount of energy released.

$E=[(9.106\times 10^{-3})\times (1.66\times 10^{-27})Kg]\times (3\times 10^8m/s)^2$

$E=136.043\times 10^{-14}J$

Therefore, the amount of energy released is, $136.043\times 10^{-14}J$