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svp [43]
4 years ago
13

A tritium nucleus is formed by combining two neutrons and a proton. the mass of this nucleus is 9.106 × 10–3 universal mass unit

less than the combined mass of the particles from which it is formed. approximately how much energy is released when this nucleus is formed.
Chemistry
2 answers:
kumpel [21]4 years ago
7 0
E = m c²

where E = energy released

m = mass of the nucleus

C= velocity of light

m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg

C = 3 x 10⁸ m/s and C² = 9 x 10¹⁶

E = 1.37 x 10 ⁻¹² J

vovangra [49]4 years ago
6 0

Answer : The amount of energy released is, 136.043\times 10^{-14}J

Explanation :

According to the Einstein equation, the energy is equal to the product of mass and the square of the speed of light.

The mathematical expression is :

E=m\times c^2

where,

E = energy

c = speed of light = 3\times 10^8m/s

m = mass of nucleus = 9.106\times 10^{-3}amu

Conversion the mass of nucleus from 'amu' into 'Kg' :

As, 1amu=1.66\times 10^{-27}Kg

So, 9.106\times 10^{-3}amu=(9.106\times 10^{-3})\times (1.66\times 10^{-27})Kg

Now put all the given values in the above formula, we get the amount of energy released.

E=[(9.106\times 10^{-3})\times (1.66\times 10^{-27})Kg]\times (3\times 10^8m/s)^2

E=136.043\times 10^{-14}J

Therefore, the amount of energy released is, 136.043\times 10^{-14}J

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