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Lana71 [14]
3 years ago
15

You are examining the DNA sequences that code for the enzyme phosphofructokinase in skinks and Komodo dragons. You notice that t

he coding sequence that actually directs the sequence of amino acids in the enzyme is very similar in the two organisms but that the surrounding sequences vary quite a bit. What is the most likely explanation for this?
A. Coding sequences are repaired more efficiently.
B. Coding sequences are replicated more efficiently.
C. Coding sequences are packaged more tightly in th e chromosomes to protect them from DNA damage.
D. Mutations in coding sequences are more likely to e deleterious to the organism than mutations in noncoding sequences.
E. Recombination between skink and Komodo dragon DNA occurred recently.
Chemistry
1 answer:
jek_recluse [69]3 years ago
8 0

Answer: D. Mutation in coding sequences are more likely to be deleterious to the organism than mutations in noncoding sequences.

Explanation: It was not likely to be that the coding sequences are replicated more often. The only possible explanation is that the mutations in coding is more likely to be deleterious to the organism than mutations because it is in a non coding sequence.

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Copper sulfate can crystalize as an anhydrate (no water in the crystal) or as three different hydrates (varying amounts of water
Maurinko [17]

Answer:

Two factors that might have a affect of which copper sulphate mineral will occur at a given location  is:

A. Copper sulphate high solubility in water

B. Also it binds nicely with the sediments  or the crystal.

Explanation:

As it is mentioned here that copper sulphate can be crystallized as an anhydrate which means that their  is no waterin those crystals or can be as of those three different hydrates whose crystal structure varies with the amount of water present in it.

The four forms are also given of the copper sulphate are:

  • Bonatite
  • Boothite
  • Chalcanthite
  • Chalcocyanite

So, the two factors that might give an affect which type of copper sulphate  mineral willoccur at a given location is:

A. The copper sulphate high solubility in water.

B. It binds extremely nicely with the sediments or say to the crystal. It is  also regulated by plants.

8 0
3 years ago
What is the pH of a 0.050 M triethylamine, (C2H5)3N, solution? Kb for triethylamine is 5.3 ´ 10-4. Question options: 1) 11.69 2)
blsea [12.9K]
<span>the pH of a 0.050 M triethylamine, is 11.70
</span>
For triehtylamine, (C_{2}H_{5})_{3}N, the reaction will be
(C_{2}H_{5})_{3}N + H_{2}O ---\ \textgreater \ ( C_{2}H_{5})_{3}NH^{+} + OH^{-}

 and we know, pH = -log[H+] and pOH = -log[OH-]

Also, pOH + pH = 14

Now, the Kb value  = 5.3 x 10^-4

And kb =  \frac{( [( C_{2}H_{5})_{3}NH^{+} ]*  OH^{-} )}{[( C_{2}H_{5})_{3}N]}

 thus, [OH-] =(5.3 ^ 10-4) ^2 / 0.050

                    =0.00516 M 

Thus, pOH = 2.30 
 pH = 14 - pOH = 11.7
6 0
3 years ago
Benzoic acid, c6h5cooh, has a ka = 6.4 x 10-5. what is the concentration of h3o+ in a 0.5 m solution of benzoic acid? 3.2 x 10-5
FinnZ [79.3K]
The answer for this issue is: 
The chemical equation is: HBz + H2O <- - > H3O+ + Bz- 
Ka = 6.4X10^-5 = [H3O+][Bz-]/[HBz] 
Let x = [H3O+] = [Bz-], and [HBz] = 0.5 - x. 
Accept that x is little contrasted with 0.5 M. At that point, 
Ka = 6.4X10^-5 = x^2/0.5 
x = [H3O+] = 5.6X10^-3 M 
pH = 2.25
(x is without a doubt little contrasted with 0.5, so the presumption above was OK to make) 
3 0
4 years ago
Problems associated with a declining population size include _____.
Rzqust [24]
<span>The correct answer is weakened economic strength. When a declning population size starts to occur and develop, the country may experience a weakened economic strength, since the power to produce and create products and services has been hindered and weakened due to its declining population.</span>
7 0
3 years ago
Read 2 more answers
The density of water at 400C is 0.992 g/mL What is the volume of 27.0 g of water at this temperature?
pantera1 [17]

Answer:

Volume of water at this temperature is 27.2 mL

Explanation:

We know that density=\frac{mass}{volume}

Here density of water is 0.992 g/mL

Here mass of water is 27.0 g

So volume=\frac{mass}{density}

                         = \frac{27.0g}{0.992g/mL}

                         = 27.2 mL

7 0
4 years ago
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