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yulyashka [42]
1 year ago
15

The number of nucleons of an isotope represents the total number of..

Chemistry
1 answer:
Elza [17]1 year ago
3 0

Answer:

The mass number (A), also called atomic mass number or nucleon number, is the total number of protons and neutrons (together known as nucleons) in an atomic nucleus. The mass number is different for each different isotope of a chemical element.

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How does energy usage compare during different seasons of the year
omeli [17]
The residential end-use sector has the largest seasonal variance, with significant spikes in demand every summer and winter. Virtually all homes that have air conditioning use electricity as the main source of cooling in the summer, while winter heating needs are met by a variety of fuels. Some homes use electric resistance heating and electric heat pumps, but even homes with other heating fuels such as natural gas or fuel oil still use some electricity to power furnace fans, boiler circulation pumps, and compressors.
The commercial sector experiences less variance in electricity use, although it shows a noticeable increase in the summer and a slight increase in the winter. Compared to the residential sector, a smaller portion of commercial sector energy consumption is devoted to heating, cooling, and ventilation. However, other energy fuels beyond electricity can be used in the commercial sector to meet both heating and cooling needs. For example, some commercial buildings use natural gas-fired chillers for cooling.
The industrial sector's demand for electricity is relatively flat (with just a slight increase in the summer) because a much smaller portion of its energy consumption (electric and otherwise) is used for heating and cooling. Economic variables generally play a larger role in industrial energy use than weather-related factors. However, seasonal changes can affect industrial activity. For example, in the refining industry, different seasonal slates of petroleum products as well as different seasonal processes may affect electricity needs.
6 0
3 years ago
What was ernest rutherfords experiment
ohaa [14]

Answer: he shot tiny alpha particles throug a piece of gold foil.

Explanation:

6 0
3 years ago
Why is the use of high-frequency radio waves a beneficial technological advancement
Lynna [10]

Answer:

I think It's C

Explanation:

due to higher waves can get easy transfers and receive those signals for most things, such as radios, TVs, phone signals etc etc

4 0
2 years ago
Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C
umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}

Given:

\left[I_2_{Equilibrium} \right] = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}

So,

\left[I_{Equilibrium} \right]^2=0.011\times 0.10

\left[I_{Equilibrium} \right]^2=0.0011

\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

3 0
3 years ago
Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.
STALIN [3.7K]

Answer: Solution A : [H_3O^+]=0.300\times 10^{-7}M

Solution B : [OH^-]=0.107\times 10^{-5}M

Solution C : [OH^-]=0.177\times 10^{-10}M

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

pH=-\log[H_3O^+]

pOH=-log[OH^-}

pH+pOH=14

[H_3O^+][OH^-]=10^{-14}

a. Solution A: [OH^-]=3.33\times 10^{-7}M

[H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M

b. Solution B : [H_3O^+]=9.33\times 10^{-9}M

[OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M

c. Solution C : [H_3O^+]=5.65\times 10^{-4}M

[OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M

7 0
2 years ago
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