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Juli2301 [7.4K]
3 years ago
15

Referring to an activity series, which of the following combinations of reactants would not produce a successful single-replacem

ent reaction?
Zn +CuSO4
Ca + MgSO4
Ag + SnSO4
K + Na2SO4

Chemistry
2 answers:
loris [4]3 years ago
8 0
 I believe the answer is Ca + MgSO4
bonufazy [111]3 years ago
8 0

<u>Answer:</u> The combination of reactants that will not undergo single displacement reaction is (Ag+SnSO_4)

<u>Explanation:</u>

Single-displacement reactions are defined as the reactions in which a more reactive metal displaces a less reactive metal from its chemical reaction. The reactivity of metal is judged by a series known as reactivity series.

A+BC\rightarrow AC+B

Metal A is more reactive than metal B.

The metal which is present above in the series is more reactive than the metal which is present below in the series.

For the given options:

<u>Option 1:</u>  Zn+CuSO_4

Zinc lies above in the series than copper and thus will easily replace copper from its chemical reaction.

Zn+CuSO_4\rightarrow ZnSO_4+Cu

<u>Option 2:</u>  Ca+MgSO_4

Calcium lies above in the series than magnesium and thus will easily replace magnesium from its chemical reaction.

Ca+MgSO_4\rightarrow CaSO_4+Mg

<u>Option 3:</u>  Ag+SnSO_4

Silver lies below in the series than tin and thus will not replace tin from its chemical reaction.

Ag+SnSO_4\rightarrow \text{No reaction}

<u>Option 4:</u>  K+Na_2SO_4

Potassium lies above in the series than sodium and thus will easily replace sodium from its chemical reaction.

2K+Na_2SO_4\rightarrow K_2SO_4+2Na

Hence, the combination of reactants that will not undergo single displacement reaction is (Ag+SnSO_4)

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Nataly_w [17]

The glass opposite to the negative electrode started to glow. Hence, option B is correct.

<h3>What is a cathode ray tube?</h3>

A cathode-ray tube (CRT) is a specialized vacuum tube in which images are produced when an electron beam strikes a phosphorescent surface.

J.J. Thomson, through his famous Cathode ray experiment, proved that all atoms contain small negatively charged particles known as electrons. In the experiment, he applied electric voltage across a cathode ray tube. a fluorescent material coating was done on the positive side. When the voltage was applied, the positive side has glowing dots.

Hence, option B is correct.

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2 years ago
Cl2 + 2OH− → Cl− + ClO− + H2O
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Cl2(g) -------> Cl-(aq) + ClO-(aq) 

2e- + Cl2(g) -------> 2Cl-(aq) [reduction] 

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4 0
3 years ago
A compound is composed of C, H and O. A 1.621 g sample of this compound was combusted, producing 1.902 g of water and 3.095 g of
vlada-n [284]

Answer: The molecular of the compound is, C_2H_3O

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=3.095g

Mass of H_2O=1.902g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.095g of carbon dioxide, \frac{12}{44}\times 3.095=0.844g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.902g of water, \frac{2}{18}\times 1.092=0.121g of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = (1.621)-[(0.844)+(0.121)]=0.656g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.844g}{12g/mole}=0.0703moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.121g}{1g/mole}=0.121moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.656g}{16g/mole}=0.041moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.041 moles.

For Carbon = \frac{0.0703}{0.041}=1.71\approx 2

For Hydrogen  = \frac{0.121}{0.041}=2.95\approx 3

For Oxygen  = \frac{0.041}{0.041}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 2 : 3 : 1

Hence, the empirical formula for the given compound is C_2H_3O_1=C_2H_3O

The empirical formula weight = 2(12) + 3(1) + 1(16) = 43 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{46.06}{43}=1

Molecular formula = (C_2H_3O_1)_n=(C_2H_3O_1)_1=C_2H_3O

Therefore, the molecular of the compound is, C_2H_3O

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3 years ago
Essentially, the oxygen we breath is
stepan [7]

Answer:

b

Explanation:

Plants need carbon dioxide and let out oxygen

3 0
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OLEGan [10]

Besides producing hydrogen ions in water, all Arrhenius acids have a few things in common. They have pH values anywhere from 0 up to 7, they taste and smell sour and they will turn pH paper pink, red, or orange.

<h3>What Arrhenius acids?</h3>

A substance that raises the concentration of H+ ions in an aqueous solution is known as an Arrhenius acid. Traditional Arrhenius acids are highly polarized covalent substances that dissociate in water to form an anion (A-) and the cation H+.

Aqueous Arrhenius acids have distinguishing characteristics that serve as a useful definition of an acid. Acids can turn blue litmus red, produce aqueous solutions with a sour taste, and react with bases and some metals (like calcium) to generate salts. The Latin word acidus/acre, which means "sour," is where the word acid originates.

Although the precise definition solely refers to the solute, the term "acid" is sometimes used to refer to an aqueous solution of an acid that has a pH lower than 8.

To learn more about Arrhenius acids from the given link:

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