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beks73 [17]
3 years ago
12

What is true about the completely simplified sum of the polynomials 3x squared y squared minus 2 x y to the power of 5 and negat

ive 3 x squared y squared plus 3 x to the power of 4 y
Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

The sum is a binomial with a degree of 6.

Step-by-step explanation:

To find : What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2+3x^4y ?

Solution :

The polynomials  3x^2y^2-2xy^5 and -3x^2y^2+3x^4y ,

The sum of polynomial is given by,

S=3x^2y^2-2xy^5+(-3x^2y^2+3x^4y)

On simplifying , we get,

S=3x^2y^2-2xy^5-3x^2y^2+3x^4y

S=-2xy^5+3x^4y

Therefore, the result obtained is a binomial with a degree of 6.

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A tech company bought a number of computers for its employees: 66 costing \$1600$1600 each, 44 costing \$1200$1200 each, and yy
daser333 [38]

Answer:

5

Step-by-step explanation:

A tech company bought a number of computers for its employees: 6 costing $1600 each, 4 costing $1200 each, and y costing $900 each, where y is a positive odd integer. what is the greatest possible value of y

Solution:

The median of a group of numbers is the middle number when the group of numbers have been arranged either in ascending of descending other. The median of an even group of numbers is the average of the two most middle most numbers while the median of an odd group of numbers is the middle number.

Since there are 6 computers costing $1600, 4 computers costing $1200 each and y computers costing $900 each. Since y is odd, hence y + 6 + 4 would be odd and the median would be the middle number.

Given that the median price = $1200, this means that the middle of the group of numbers is $1200

900, 900, ..., 1200, 1200, 1200, 1200, 1600, 1600, 1600, 1600, 1600, 1600

Since y is odd, for the median price to be $1200, y has to be 3 or 5.

If y = 3:

900, 900, 900, 1200, 1200, 1200, 1200, 1600, 1600, 1600, 1600, 1600, 1600

median = $1200

If y = 5:

900, 900, 900, 900, 900, 1200, 1200, 1200, 1200, 1600, 1600, 1600, 1600, 1600, 1600

Median = $1200

Therefore the greatest possible value of y is 5

5 0
3 years ago
I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
     Therefore, we have:

\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
8 0
3 years ago
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