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svetoff [14.1K]
3 years ago
4

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction caco3(s)→cao(s)+co2(g)

what is the mass of calcium carbonate needed to produce 61.0 l of carbon dioxide at stp? express your answer with the appropriate units?
Chemistry
1 answer:
12345 [234]3 years ago
5 0
Answer is: 227.3 grams of <span>of calcium carbonate needed.
</span>Chemical reaction: CaCO₃ → CaO + CO₂.
V(CO₂) = 61.0 L.
n(CO₂) = V(CO₂) ÷ Vm.
n(CO₂) = 61 L ÷ 22.4 L/mol.
n(CO₂) = 2.723 mol.
From chemical reaction: n(CO₂) : n(CaCO₃) = 1 : 1.
n(CaCO₃) = 2.273 mol.
m(CaCO₃) = n(CaCO₃) · M(CaCO₃).
m(CaCO₃) = 2.273 mol · 100 g/mol.
m(CaCO₃) = 227.3 g.
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