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Mama L [17]
3 years ago
8

If air is 80 percent nitrogen and 20 percent oxygen by volume what is density

Chemistry
1 answer:
Evgen [1.6K]3 years ago
5 0
1 mol of any gas or mix of gases at STP conditions will have a volume of 22.4 L. Since the problem doesn’t said what are the conditions I will asume that are STP condition and the volume of one mole of the mix will have a volume of 22.4 L.

You may know that density is
D=m/v

In one mole of air I will have 80% of Nitrogen (N2) and 20% oxygen (O2).

So the mass of one mole of air will be

14 x2x0.80+16x2x0.20 = 22.4 g + 6.4 g = 28.8 g

D= 28.8/22.4 = 1.28 g/L

Of course if the temperature is higher the density will be smaller because the volume of one mole will be bigger and viceversa if the temperature decrease. Also if the pressure is different than one atm the volume of a mol will change.
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Meterologists track the location of Jet Streams. How do jet streams influence the weather? *
Lera25 [3.4K]

Answer:

Explanation:

By moving weather systems quickly

I think this is correct

3 0
2 years ago
If phosphorous has 5 valence electrons, how many does sulfur have?
VARVARA [1.3K]

Answer:

6

Explanation:

The atomic number for phosphorous is 15, meaning that it has 15 electrons (and protons). The first and second shells would be filled up with 2 and 8 electrons respectively, leaving 5 which goes on the third shell, which is also the valence shell, meaning phosphorous has 5 valence electrons.

Since the atomic number of sulfur is 16, the first and second shells are also filled up with 2 and 8 electrons respectively, leaving 6 to be on the third shell, the valence shell. Hence, sulfur has 6 valence electrons.

5 0
1 year ago
I HAVE ANSWER
Agata [3.3K]
<span>11.2G is the answer to this problem.
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7 0
3 years ago
Read 2 more answers
2NO (g) + O2 (g) →2NO2 (g) At equilibrium [NO] = 2.4 × 10 -3 M, [O2] = 1.4 × 10 -4 M, and [NO2] = 0.95 M.
azamat

Answer:

K=1.12x10^9

Explanation:

Hello there!

Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:

K=\frac{[NO_2]^2}{[NO]^2[O_2]}

Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:

K=\frac{(0.95)^2}{(0.0024)^2(0.00014)}\\\\K=1.12x10^9

In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.

Best regards!

4 0
3 years ago
Examine the following equations.
Alex

Answer: (A) and (D)

Options (A) and (D) represent beta decay.

Explanation:

It is very simple to find  beta decay in a nuclear reaction. In beta decay , neutron breaks down into a proton and an electron. After that electron is emitted from the nucleus,while proton remains inside nucleus. The resulting daughter nuclei will have one more proton and one less neutron.

8 0
3 years ago
Read 2 more answers
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