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yuradex [85]
3 years ago
9

Please help me solve it​

Mathematics
1 answer:
kkurt [141]3 years ago
8 0

Answer:

<h2>I SUGHESTED THE ANSWER IS A</h2>
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Find the cubes of the following numbers: a) 21 b) 55 c) 302
otez555 [7]

Answer:

a)9261

b)166375

c)27543608

Step-by-step explanation:

21 x 21 x 21 = 9261

55 x 55 x 55 = 166375

302 x 302 x 302 = 27543608

7 0
3 years ago
6b+bx=ax+a2 solve for x
Shkiper50 [21]

6b+bx=ax+a^2\implies 60-a^2+bx=ax\implies 60-a^2=ax-bx \\\\\\ \stackrel{\underset{\qquad \downarrow }{\textit{common factoring}}}{60-a^2=x(a-b)}\implies \cfrac{60-a^2}{a-b}=x

8 0
2 years ago
Read 2 more answers
Cody wants to watch a new movie that is three hours long.
Ne4ueva [31]

Answer:

1/2 of an hour

Step-by-step explanation:

Well firstly we must find the amount of minutes spent watching. Which is 3 * 60  = 180mins.Then we find 1/6 of 180 = 30We now know Cody has watch 30 minute of the movie.To find what fraction this is of an hour we divide it by minutes in an hour:30/60 which is 1/2Therefore the answer is 1/2 of an hour


3 0
3 years ago
Read 2 more answers
A special type of password consists of 3 different letters of the alphabet, and the two different numbers, where each letter and
Phoenix [80]

Answer:

There can be 14,040,000 different passwords

Step-by-step explanation:

Number of permutations to order 3 letters and 2 numbers (total 5)

(AAANN, AANNA,AANAN,...)

= 5! / (3! 2!)

= 120 / (6*2)

= 10

For each permutation, the three distinct (English) letters can be arranged in

26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways

For each permutation, the two distinct digits can be arranged in

10!/(10-2)! = 10!/8! = 10*9 = 90 ways.

So the total number of distinct passwords is the product of all three permutations,

N = 10 * 15600 * 90 = 14,040,000

7 0
3 years ago
Plz help asappppp I’ll give brainliest
Elena L [17]

Answer: c I think

Step-by-step explanation:

7 0
3 years ago
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