Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via
<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em> ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>
where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.
P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)
… = P(<em>Z</em> < 0.24)
… ≈ 0.5948
<span>(3x-4)+(x+3)^2
= 3x - 4 + x^2 + 6x + 9 .........(expand using (a+b)^2 = a^2 + 2ab + b^2)
= x^2 + 9x + 5 ..........(combine like terms and simplify)
hope that helps</span>
Because three points of the angle have to be named ex; angle ABC
<span>2 • (7v + 11) over
4 is your answer :)</span>
