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Vikki [24]
3 years ago
8

Is cos 314 positive, negative or zero

Mathematics
1 answer:
Dafna1 [17]3 years ago
7 0
Cos (314) = .694 is positive
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Find the percent increase. 57 people to 65 people
s2008m [1.1K]

Answer:

62%

Step-by-step explanation:

8 0
3 years ago
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$800 is deposited in an account that pays 9% annual interest compounded annually. Find the balance after four years
tester [92]

Answer:

<h2>$1,129.27</h2>

Step-by-step explanation:

Compounded interest formula is

A=P(1+\frac{r}{n})^{nt}

Where A is the final amount, P is the principal, r is the anual interest in decimal, n is the numer of compounded periods in one year and t is the time in years.

P=\$800\\r=0.09\\n=1\\t=4

Notice that n=1, because the interest is compounded anually, if the interest is compounded, then n=12, because there would be 12 compound periods in one year.

Then, we replace all these vaules in the formula

A=P(1+\frac{r}{n})^{nt}\\A=800(1+\frac{0.09}{1})^{1(4)}=800(1.09)^{4}\\ A=1,129.26

Therefore, after 4 years, the amount would be $1,129.27.

7 0
3 years ago
A shipping container will be used to transport several 80-kilogram crates across the
Leno4ka [110]

Answers:

  • The inequality to solve is 80x+6300 \le 26500
  • The solution to the inequality is x \le 252.5
  • Interpretation: The most crates we can load is 252 since we can only load a positive whole number of crates, and because 253 is too many.

==============================================================

Explanation:

x = number of 80-kilogram crates

x is some positive whole number

1 crate weighs 80 kilograms, so x of them will weigh 80x kilograms.

This is added on top of the 6300 kg from the other cargo already on board.

We have a total weight of 80x+6300. Let's call this T.

So T = 80x+6300

We want T to be 26500 or smaller. Otherwise, we've gone over capacity.

This must mean we want T \le 26500 which is the same as saying 80x+6300 \le 26500 after replacing T with 80x+6300.

---------------------------

Let's follow PEMDAS in reverse to isolate x

80x+6300 \le 26500\\\\80x+6300-6300 \le 26500-6300 \ \text{ ... subtract 6300 from both sides}\\\\80x \le 20200\\\\\frac{80x}{80} \le \frac{20200}{80} \ \text{ ... divide both sides by 80}\\\\x \le 252.5\\\\

The inequality sign stays the same the entire time. It would only flip if we divided both sides by a negative number.

In the last step, we get a decimal value. However, as stated earlier, x is a positive whole number.

We cannot round to 253 because that's too high. We can check x = 253 is too high by noticing that...

80x+6300 = 80*253+6300 = 26,540

which is over the 26,500 mark by 40 kg

So we must round down to the nearest whole number and find that x = 252 is the largest x value possible. Let's check to see if we're under the weight limit

80x+6300 = 80*252+6300 = 26,460

We're under the 26,500 weight limit (with 40 kg to spare)

In short, the most crates that we can load is 252 crates in addition to the other cargo that collectively weighs 6300 kg (which may or may not consist of those 80-kilogram crates).

5 0
3 years ago
Are all the rectangles faces the same size
inn [45]
If you mean cuboid then no and if you mean rectangle but sides not faces then yes
3 0
3 years ago
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-19.78 is rational or irrational
Bess [88]
Is irrational because Star with number more and 1.
7 0
3 years ago
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