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4 years ago

Find the height of X. Having a hard time figuring this out

Mathematics

1 answer:

Delvig [45]4 years ago

8 0

Use the pythagorean theorem:
$a^2 +b^2 = c^2$

where c is the hypotenuse of the triangle.

$x^2 +12^2 = 14^2 \\ \\ x^2 +144 = 196 \\ \\ x^2 = 52 \\ \\ x = \sqrt{52} = 2 \sqrt{13}$

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Antonio has $350 to spend on skis. Sales tax is 6%. Decide if each description of a price and discount, plus sales tax, represen

kobusy [5.1K]

Answer:721

Step-by-step explanation:It is 721 because when you have a sale tax you add it and that 100%+6%=106%=1.06 then 350x1.06 which equals to 371. Since it’s sales tax then 371+350=721. So it is $721.

6 0

4 years ago

Read 2 more answers

Ralph wants to estimate the percentage of coworkers that use the company's healthcare. He asks a randomly selected group of 200

mel-nik [20]

Answer:

Step-by-step explanation:

The parameter is used to measure the population or in other words the measurement taken from a population is known as parameter. Here, the population will be all the co-workers that use company's healthcare. The percentage calculated for all co-workers that use company's healthcare will be the measurement calculated from population. Thus, the parameter will be the percentage of all the co-workers that use the company's healthcare.

8 0

4 years ago

Solve for x.

victus00 [196]

The answer is 370 because you need to work it out.

Basically what I did was look at the first number, 12, and the answer to the equation and saw that 12 x 10 would be 120. And 360 + 10 would be 370.

It fits in perfectly.

12(370 - 360) = 120
370 - 360 = 10
12(10) = 120

So x = 370

8 0

4 years ago

Help please...........

AlladinOne [14]

The answer is B because the yintercept is -2

8 0

3 years ago

Find an for the arithmetic series with s16 = -288 And a1 =-21

Maru [420]

If $d$ is the common difference between terms in the sequence $\{a_n\}$ , then

$a_1=-21$
$a_2=a_1+d=-21+d$
$a_3=a_2+d=-21+2d$
...
$a_n=a_{n-1}+d=\cdots=-21+(n-1)d$

You're told that $S_{16}=-288$ (the sum of the first 16 terms in the sequence, presumably). Well, we know that

$S_{16}=\displaystyle\sum_{n=1}^{16}a_n=\sum_{n=1}^{16}(-21+(n-1)d)$
$S_{16}=\displaystyle(-21-d)\sum_{n=1}^{16}1+d\sum_{n=1}^{16}n$

Recall that

$\displaystyle\sum_{n=1}^kn=\frac{k(k+1)}2$

so that we have

$-288=16(-21-d)+\dfrac{16(16+1)}2d\implies d=\dfrac25$

So we get

$\begin{cases}a_1=-21\\\\a_n=-21+\dfrac25(n-1)\end{cases}$

8 0

3 years ago