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3 years ago

Expand.Your answer should be a polynomial in standard form.(2x- 4) (2x- 6) =

Mathematics

2 answers:

ElenaW [278]3 years ago

6 0

Answer:

4x^2-20x+24

Step-by-step explanation:

Use FOIL

4x^2-20x+24

34kurt3 years ago

4 0

Answer:4x^2-20x+24

step by step:

4x^2-12x-8x+24 further addition and final answer is obtained

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Factor the polynomial: x(5x-8)-2(5x-8)

sertanlavr [38]

x(5x-8)-2(5x-8) =(5x-8)(x-2)
Answer is C. (5x-8)(x-2)

3 0

3 years ago

5. How many tenths are in 2 2/10

Neko [114]

Answer:

2 tenths

Step-by-step explanation:

In decimal form: 2.2

You can see that in the tenths place, there is a 2, so 2 tenths.

6 0

3 years ago

Write the equation for each translation of the graph of y=| 1/2x-2|+3

Dafna11 [192]

Minimum is (4,3) and Vertical intercept is (0,5) correct me if I’m wrong

5 0

2 years ago

An open box is made from an 8 by ten-inch rectangular piece of cardboard by cutting squares from each corner and folding up the

natka813 [3]

Please find the attachment.

Let x represent the side length of the squares.

We have been given that an open box is made from an 8 by ten-inch rectangular piece of cardboard by cutting squares from each corner and folding up the sides. We are asked to find the volume of the box.

The side of box will be $8-x-x=8-2x$ and $10-x-x=10-2x$ .

The height of the box will be $x$ .

The volume of box will be area of base times height.

$\text{Volume of box}=(8-2x)(10-2x)\cdot x$

Now we will use FOIL to simplify our expression.

$\text{Volume of box}=(80-16x-20x+4x^2)\cdot x$

$\text{Volume of box}=(80-36x+4x^2)\cdot x$

Now we will distribute x.

$\text{Volume of box}=80x-36x^2+4x^3$

$V(x)=80x-36x^2+4x^3$

Therefore, the volume of the box would be $V(x)=80x-36x^2+4x^3$ .

6 0

3 years ago

If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime

Yuri [45]

Answer:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

Step-by-step explanation:

Given two positive integers $r$ and $s$ .

To check whether $\small \frac{r}{s}$ is an integer:

Condition (1):

Every factor of $s$ is also a factor of $r$ .

$r \geq s$

Let us consider an example:

$s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2$

$\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10$

which is an integer.

Actually, in this situation $s$ is a factor of $r$ .

Condition 2:

Every prime factor of s is also a prime factor of r.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

$r = 2^2\cdot 5\\s =2^4\cdot 5$

$\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}$

which is not an integer.

So, the answer is:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

8 0

3 years ago

Expand.Your answer should be a polynomial in standard form.(2x- 4) (2x- 6) =​

Expand.Your answer should be a polynomial in standard form.(2x- 4) (2x- 6) =