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vova2212 [387]
3 years ago
9

Equipment acquired at the beginning of the year at a cost of $340,000 has an estimated residual value of $45,000 and an estimate

d useful life of 10 years. determine the following. round your answer for the straight-line rate to one decimal place, if necessary.
Mathematics
2 answers:
mylen [45]3 years ago
4 0
Using straight-line rate, we are finding the annual depreciation with equal annual reductions.

Thus, total depreciation = 340,000 - 45,000 = 295,000
Duration of depreciation = 10 years
Therefore, using the straight-line rule, the annual depreciation is 29,500.

Answer: straight-line rate  is $29,500 per year.

Note: please proof question before posting.  Missing values and typos will delay your answer.
SCORPION-xisa [38]3 years ago
3 0
Straight-line rate is the depreciation rate each year
Since the useful life is 10 years So depreciation rate is
100%/10=10%

The answer is 10%
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<h3>Answer:  cos(76)</h3>

=========================================================

Explanation:

The original expression is of the pattern cos cos + sin sin. This pattern matches the second identity in the hint. Specifically, we'll say the following:

cos(A - B) = cos(A)cos(B) + sin(A)sin(B)

cos(A)cos(B) + sin(A)sin(B) = cos(A - B)

cos(94)cos(18) + sin(94)sin(18) = cos(94 - 18)

cos(94)cos(18) + sin(94)sin(18) = cos(76)

----------

We can verify this by use of a calculator. Make sure your calculator is in degree mode.

  • cos(94)cos(18) + sin(94)sin(18) = 0.24192
  • cos(76) = 0.24192

Both expressions give the same decimal approximation, so this helps confirm the two expressions are equal. You could also use the idea that if x = y, then x-y = 0. Through this method, you'll subtract the left and right hand sides and you should get (very close to) zero.

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2 years ago
What is the additive inverse of -96
timofeeve [1]
The correct answer is 96.
4 0
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Serga [27]
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5 0
3 years ago
What are the solutions to the equation (2x – 5)(3x – 1) = 0?
user100 [1]

Answer: x=\frac{5}{2}, x=\frac{1}{3}

Explanation:

The equation is:

(2x-5)(3x-1)=0

The term on the left consists of a product of two different factors: therefore, this product can be zero if either the first term (2x-5) or the second term (3x-1) is equal to zero.

This means that we can solve separately for the two terms:

2x-5=0\\3x-1=0

Solving the first equation:

2x-5=0\\2x=5\\x=\frac{5}{2}

Solving the second equation:

3x-1=0\\3x=1\\x=\frac{1}{3}

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