Multiply the following complex numbers: (7+2i)(2+3i)

Mathematics

2 answers:

Law Incorporation [45]3 years ago

7 0

When u multiply these two u should get 6i^2+25i+14.

neonofarm [45]3 years ago

6 0

Answer:

$8+25i$

Step-by-step explanation:

Given expression,

$(7+2i)(2+3i)$

$=7(2+3i) + 2i(2+3i)$ ( Distributive property )

$=7(2) + 7(3i) + 2i(2) + 2i(3i)$ ( Distributive property )

$=14+21i+4i+6i^2$

$=14+(21+4)i-6$ ( i² = -1 )

$=14+25i-6$

$=8+25i$

Hence,

$(7+2i)(2+3i)=8+25i$

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Which value is not part of the five-number summary needed for a box plot of this data?

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5 0

3 years ago

Read 2 more answers

Please help and show work and steps

ki77a [65]

Answer:

I and III

Step-by-step explanation:

On a unit circle, the only two angles whose sine is $-\dfrac{\sqrt{3}}{2}$ are $\dfrac{4\pi}{3}$ and $\dfrac{5\pi}{3}$ , otherwise known as $-\dfrac{\pi}{3}$ . Therefore, the correct answers are I and III. You can see the unit circle below, where the y coordinates of the above angles show $-\dfrac{\sqrt{3}}{2}$ .