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sesenic [268]
3 years ago
15

How do you make x the subject of the formula when your formula is y= abx? Please can you show me how you worked it out if you an

swer it as well thank you
Mathematics
1 answer:
GrogVix [38]3 years ago
7 0
If you want to solve for x you have to get x alone on one side of the equals sign. In order to do that you have to get rid of the stuff on the same side by doing the opposite operation so that it cancels. What you do on one side you do on. the other side to keep the equation true.

y= abx

a and b are being multiplied by x so divide by ab to cancel them out (ab/ab is 1).

y= abx/ab (ab cancels)

now divide the other side by ab to keep the equation true.

y/ab= x

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Find the product of the expression:<br> (5p^3) (-1m^8p^2)
Rainbow [258]

Answer:

We conclude that:

  • \left(5p^3\right)\:\left(-1m^8p^2\right)=-5p^5m^8

Step-by-step explanation:

Given the expression

\left(5p^3\right)\:\left(-1m^8p^2\right)

Apply the rule:

a\left(-b\right)=-ab

so the expression becomes

\left(5p^3\right)\left(-1\cdot \:m^8p^2\right)=-5p^3\cdot \:1\cdot \:m^8p^2

Apply the rule:

a^b\cdot \:a^c=a^{b+c}

so the expression becomes

                             =-5p^{3+2}\cdot \:1\cdot \:m^8         ∵ p^3p^2=p^{3+2}

                             =-5p^5\cdot \:1\cdot \:m^8

                             =-5p^5m^8

Therefore, we conclude that:

  • \left(5p^3\right)\:\left(-1m^8p^2\right)=-5p^5m^8
7 0
3 years ago
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
A running track has a straight stretch that measures 200m at the ends there are
Tju [1.3M]

Answer:

300.57 m

Step-by-step explanation:

7 0
3 years ago
93 divided by 3 using repeated subtraction
Naily [24]

93/3=31 Answer is 31

8 0
3 years ago
Read 2 more answers
(10 points) <br> Solve for x. Assume that the lines which appear to be tangent are tangent
Ganezh [65]

The two tangent lines for each circle are the same length. Set the equations to equal and solve for x.

1. 4x + 3 = 3x +12

Subtract 3x from each side:

x +3 = 12

Subtract 3 from both sides:

x = 9

2. -2 + x = 2x -7

Subtract 2x from both sides:

-2 - x =  -7

Add 2 to each side:

-x = -5

Multiply both sides by -1:

x = 5

8 0
3 years ago
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