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A crossover trial is a type of experiment used to compare two drugs. Subjects take one drug for a period of time and then switch

zysi [14]

Answer:

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369$

$df=n-1=7-1=6$

$p_v =2*P(t_{(6)}$

We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs

Step-by-step explanation:

We have the following info given by the problem

Subject 1 2 3 4 5 6 7

Drug A 6 3 4 5 7 1 4

Drug B 5 1 5 5 5 2 2

x=value for drug A , y = value for drug B

x: 6 3 4 5 7 1 4

y: 5 1 5 5 5 2 2

We want to verify if the mean response differs between the two drugs then the system of hypothesis for this case are:

Null hypothesis: $\mu_y- \mu_x = 0$

Alternative hypothesis: $\mu_y -\mu_x \neq 0$

We can begin calculating the difference $d_i=y_i-x_i$ and we obtain this:

d: -1, -2, 1, 0, -2, 1, -2

Now we can calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}=-0.714$

Now we can find the the standard deviation for the differences, and we got:

$s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}}=1.38$

And now we can calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369$

Now we can find the degrees of freedom given by:

$df=n-1=7-1=6$

We can calculate the p value, since we have a two tailed test the p value is given by:

$p_v =2*P(t_{(6)}$

We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs

7 0

3 years ago

The 8th and 20th terms of an arithmetic sequence are 20 and 56 respectively. What is the 1st term of the sequence.

Ostrovityanka [42]

Answer:

Step-by-step explanation:

$a_n=a_1+d(n-1)\\\\a_8=a_1+d\cdot7\\\\a_{20}=a_1+d\cdot19\\\\a_{20}-a_8=a_1+19d-(a_1+7d)=12d\\\\56-20=2d\\\\12d=36\\\\d=3\\\\\\ a_1+3\cdot7=20\\\\a_1=20-21=-1$

6 0

2 years ago

Ava wants to ride her bicycle more than 75 miles this week. She has already ridden her bicycle 16 miles. Which inequality could

Whitepunk [10]

Answer:

I think it may be 5m + 16 < 75

Step-by-step explanation:

I don't know if its wrong

6 0

2 years ago

From the measurements of the legs of a right triangle measuring 3cm, 4cm and the hypotenuse of the same 5cm, calculate the measu

WARRIOR [948]

Answer:

3cm and 4cm addition

7cm and 5cm subtract

2cm answer

3 0

2 years ago

Find the area of ABC with vertices A(3,-6), B(5,-6), and C(7,–9).

stellarik [79]

Area of a triangle ABC with the given vertices is 3 square units.

Given that, the vertices of a triangle ABC, A(3,-6), B(5,-6), and C(7,–9).

<h3>What is the area of triangle formula in coordinate geometry?</h3>

In Geometry, a triangle is a three-sided polygon that has three edges and three vertices. The area of the triangle is the space covered by the triangle in a two-dimensional plane.

Area of a triangle = $\frac{1}{2} ( |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|)$

Here, (x1, y1) = A(3,-6), (x2, y2) = B(5,-6), and (x3, y3) = C(7,–9)

Now, the area of a triangle = 1/2 (|3(-6+9)+5(-9+6)+7(-6+6)|)

= 1/2 (|3(3)+5(-3)+7(0)|)

= 1/2 (|(9-15)|)

= 1/2 × 6

= 3 square units

Therefore, area of a triangle ABC with the given vertices is 3 square units.

To learn more about the area of a area of triangle with vertices visit:

brainly.com/question/26633662.

#SPJ1

7 0

1 year ago